努力做while循环但是循环结果只输出了一种
```c
#include
#include
#include
#include
int main()
{
clock_t start,end;
int x=100;
int da=1, zhong=1, xiao=2;
int cnt=0;
while(da<=33){
while(zhong<=99){
while(xiao<=199){
if ( xiao*0.5 + zhong*2 + da*3 == 100 ) {
printf("可以用%d个小马加%d个中马加%d个大马扛100担物品\n", xiao, zhong, da );
cnt++;
}
xiao+=2;
}
zhong++;
}
da++;
}
end=clock();
printf("程序运行时间为:%5.lf time\n",difftime(end,start));
printf("当每一种马至少有一只,共:%d种方法",cnt);
return 0;
}
我用for做出了答案但是while做不出来


#include<stdio.h>
#include<time.h>
#include<dos.h>
#include<conio.h>
int main()
{
clock_t start=clock(),end;
int x=100;
int da=1, zhong=1, xiao=2;
int cnt=0;
while(da<=33){
zhong = 1;
while(zhong<=99){
xiao = 2;
while(xiao<=199){
if ( xiao*0.5 + zhong*2 + da*3 == 100 ) {
printf("可以用%d个小马加%d个中马加%d个大马扛100担物品\n", xiao, zhong, da );
cnt++;
}
xiao+=2;
}
zhong++;
}
da++;
}
end=clock();
printf("程序运行时间为:%5.lf time\n",difftime(end,start));
printf("当每一种马至少有一只,共:%d种方法",cnt);
return 0;
}