如何用最基础的C语言解答此题

如何用C语言中的枚举与结构体解答此题
freshman求指教，不含指针等内容

根据题目给出数据，定义枚举类型和数据结构。然后编写输入数据的函数（也可以考虑写死）。然后就是一些查询函数，外面要写个循环，因为查询是对于一辆车的

代码：

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>

//车辆名称枚举
enum eCarName
{
    ACKERMANN=1,
    MECANUM,
    CCGT,
    ELEMENTO,
    AMGONE
};

//车辆状态枚举
enum eCarState
{
    STOP=1,
    ORIGIN,
    CURRENT,
    LIGHT,
    SCURVED
};

//定义车辆结构
typedef struct CAR
{
    eCarName name;
    eCarState state;
    double price; //价格
    char level;  //等级
};

//打印函数
void count(struct CAR car[])
{
    int i = 0;
    printf("显示所有车辆信息\n");
    printf("#####################\n");
    for ( i = 0; i < 8; i++)
    {
        if (car[i].name == ACKERMANN)
            printf("ACKERMANN,");
        else if (car[i].name == MECANUM)
            printf("MECANUM,");
        else if (car[i].name == CCGT)
            printf("CCGT,");
        else if (car[i].name == ELEMENTO)
            printf("ELEMENTO,");
        else if (car[i].name == AMGONE)
            printf("AMGONE,");

        if (car[i].state == STOP)
            printf("STOP,");
        else if (car[i].state == ORIGIN)
            printf("ORIGIN,");
        else if (car[i].state == CURRENT)
            printf("CURRENT,");
        else if (car[i].state == LIGHT)
            printf("LIGHT,");
        else if (car[i].state == SCURVED)
            printf("SCURVED,");

        printf("%.2lf,%c\n", car[i].price, car[i].level);
    }
}

//查询函数
void priceCom(struct CAR car[])
{
    int i = 0;
    printf("车辆价格大于2000\n");
    printf("#####################\n");
    for ( i = 0; i < 8; i++)
    {
        if (car[i].price > 2000)
        {
            if (car[i].name == ACKERMANN)
                printf("ACKERMANN,");
            else if (car[i].name == MECANUM)
                printf("MECANUM,");
            else if (car[i].name == CCGT)
                printf("CCGT,");
            else if (car[i].name == ELEMENTO)
                printf("ELEMENTO,");
            else if (car[i].name == AMGONE)
                printf("AMGONE,");

            if (car[i].state == STOP)
                printf("STOP,");
            else if (car[i].state == ORIGIN)
                printf("ORIGIN,");
            else if (car[i].state == CURRENT)
                printf("CURRENT,");
            else if (car[i].state == LIGHT)
                printf("LIGHT,");
            else if (car[i].state == SCURVED)
                printf("SCURVED,");

            printf("%.2lf,%c\n", car[i].price, car[i].level);
        }
    }
}

//查询状态
void statusCom(struct CAR car[], int sta)
{
    int i;
    eCarState state;
    switch (sta)
    {
    case 1:state = STOP; break;
    case 2:state = ORIGIN; break;
    case 3:state = CURRENT; break;
    case 4:state = LIGHT; break;
    case 5:state = SCURVED; break;
    }
    for (i = 0; i < 8; i++)
    {
        if (car[i].state == state)
        {
            if (car[i].name == ACKERMANN)
                printf("ACKERMANN,");
            else if (car[i].name == MECANUM)
                printf("MECANUM,");
            else if (car[i].name == CCGT)
                printf("CCGT,");
            else if (car[i].name == ELEMENTO)
                printf("ELEMENTO,");
            else if (car[i].name == AMGONE)
                printf("AMGONE,");

            if (car[i].state == STOP)
                printf("STOP,");
            else if (car[i].state == ORIGIN)
                printf("ORIGIN,");
            else if (car[i].state == CURRENT)
                printf("CURRENT,");
            else if (car[i].state == LIGHT)
                printf("LIGHT,");
            else if (car[i].state == SCURVED)
                printf("SCURVED,");

            printf("%.2lf,%c\n", car[i].price, car[i].level);
        }
    }

}

int main()
{
    struct CAR a[8] = { {ACKERMANN,ORIGIN,1000,'a'},{MECANUM,STOP,5000,'a'},
        {CCGT,CURRENT,100,'b'},{ELEMENTO,LIGHT,2100,'c'},
        {CCGT,ORIGIN,1300,'d'},{MECANUM,STOP,6200,'b'},
        {CCGT,CURRENT,1500,'a'},{ELEMENTO,LIGHT,4800,'a'} };

    int sta;

    count(a);  //打印函数

    priceCom(a); //

    printf("按照状态查询车辆\n");
    printf("#####################\n");
    printf("请输入状态：");
    scanf("%d", &sta);
    statusCom(a, sta);


    return 0;
}

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