将python格式转化为C语言格式

C语言怎么将一段英文遍历为每个单词
例如下面的python是这样子的,但是用C怎么表达出来

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输入这段话
Youth is not a time of life; it is a state of mind; it is not a matter of rosy cheeks, red lips and supple knees; it is a matter of the will, a quality of the imagination, a vigor of the emotions; it is the freshness of the deep springs of life.

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我想要达到的结果

用C语言写出Python这样的结果

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#include <stdio.h>
#include <string.h>

int main()
{
    char str[250] = "Youth is not a time of life; it is a state of mind; it is not a matter of rosy cheeks, red lips and supple knees; it is a matter of the will, a quality of the imagination, a vigor of the emotions; it is the freshness of the deep springs of life.";
    for(int i=0; i<strlen(str); i++)
    {
        printf("%c", str[i]);
        if(str[i] == ' ') // 遇空格换行 
            printf("\n");
    }
    return 0;
}

搜索字符串中的空格,遇到空格就换行

#include <stdio.h>
int main()
{
    char s[1000],i=0;
    gets(s);
    while(a[i] != '\0')
    {
        if(a[i] != ' ')
            printf("%c",a[i]);
        else
            printf("\n");
    }
    return 0;
}
#include <stdio.h>

int main() {
  char str[255];
  while (scanf("%s", str) == 1)
    printf("%s\n", str);
  return 0;
}

有帮助请采纳

img

#include<stdio.h>
#include<string.h>
#define max 150    //句子总单词数最大值 
#define lmax 25 //句子单个单词字母总数最大值 
int isc(char t)    //判断一个字符是不是字母
{
    if((t<='z'&&t>='a')||(t<='Z'&&t>='A'))
        return 1;
    else
        return 0;
}
int isw(char t[],int b,int e)//判断字符串从下标b开始到下标e是不是一个单词
{
    int flag=1;
    for(int i=b; i<=e; i++)//下标b开始到下标e,中间有不是字母的,返回
    {
        if(isc(t[i])==0)
        {
            return 0;
        }
    }
    if(b>0)//不是字符串第一个字符
    {
        if(isc(t[b-1])==0&&isc(t[e+1])==0)//下标b-1和下标e+1不是字母,返回
        {
            return 1;
        }
    }
    else
    {
        if(isc(t[e+1])==0)
        {
            return 1;
        }
    }
    
    return 0;
}
void prin(char t[],int b,int e)//打印字符串从下标b开始到下标e之间的内容
{
    for(int i=b; i<=e; i++)
    {
        putchar(t[i]);
    }
    printf("\n");
}
int main()
{
    char t[max]= {' '};
    char wt[max][lmax];
    while(t)
    {
        gets(t);
        int count=0;
        int len=strlen(t);
        int Left=0,Right=0;//左指针Left,右指针Right 
        int p;
        for(Left=0; Left<len; Left++)
        {
            for(Right=0; Right<len-Left; Right++)
            {
                if(isw(t,Left,Left+Right)==1)//判断从左指针到右指针,之间是不是一个单词 
                {
                    prin(t,Left,Left+Right);
                    count ++;
                    break;
                }
            }
        }
        printf("\n");
        printf("单词数:%d\n",count);
        printf("输入quit退出\n");
        if(strcmp(t,"quit")==0)
            break;
    }
    return 0;
}

虽然已经采纳了,可以参考

#include <stdio.h>
#include <string.h>

int main(int, char **)
{
    printf("请输入一段英文句子:");

    char sentence[1024 + 1];
    (void)fgets(sentence, sizeof(sentence) - 1, stdin);

    char delim[] = " \n";
    char *t = strtok(sentence, delim);
    while (t != NULL)
    {
        puts(t);
        t = strtok(NULL, delim);
    }
}