一个表达式怎么提取出系数和选项。(语言-python)

Ax**3+Bcos(x+y)+Cexp(-x**2)-bx+cy
怎么提取出。(系数与项之间有⭐，这里没显示出来)
A x3
B cos(x+y)
C exp(-x2)
-b x
c y
A x3
B cos(x+y)
C exp(-x2)
-b x
c y

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下有代码，可直接复制使用。如有帮助，敬请采纳，你的采纳是我前进的动力，O(∩_∩)O谢谢！！！！！！！！
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测试公式
A*x**3+B*cos((x+y)+(x1*x-y**y1))+C*exp(-x**2)-b*x+c*y
A*x**3+B*cos((x+y)+(x1*x-y**y1))+C*x*exp(-x**2)-b*x+c*y*x
A*x**3+B*cos((x+y)+(x1*x-y**y1))+C*x*exp(-x**2)-b*x+c*y*x+A/B*x+B/A*y
不可完成:系数相同的表达式，有这方面的要求再增加

import re

representation1 = "A*x**3+B*cos(x+y)+C*exp(-x**2)-b*x+c*y"
representation1 = representation1.replace(' ','')
if representation1[0] not in '-+':
    representation1 = '+' + representation1
representation2 = representation1.replace('**', '^')

# 去掉最短括号,防干扰
# representation3 = re.sub('\(.*?\)', '', representation2)
brackets_num_left = 0
brackets_num_right = 0
representation3 = representation1
replace = ''
for x in representation1:
    if '(' in replace:
        replace += x
    if x == '(':
        if replace == '':
            replace = x
        brackets_num_left += 1
    if x == ')':
        brackets_num_right += 1
    if replace != '' and brackets_num_left == brackets_num_right:
        representation3 = representation3.replace(replace, '')
        replace = ''
# 获取系数
系数 = re.findall('[+\-].*?[A-Za-z]', representation3)
# 通过系数获取系数项
result = {}
result_str = ''
for x_i in range(len(系数)):
    try:
        res = re.findall(f'\{系数[x_i]}(.*?)\{系数[x_i + 1]}', representation1)
        result[系数[x_i]] = res[0]
    except:
        result[系数[x_i]] = representation1.split(系数[-1])[-1]
    result_str += 系数[x_i]+','+result[系数[x_i]]+','

print(result_str[:-1])

import re

F1 = "A*x**3+B*cos(x+y)+C*exp(-x**2)-b*x+c*y"

r = re.findall('(\(.*?\))', F1)
d = dict({str(i) *4: v for i, v in enumerate(r)}, **{"^^^^": "**","+-": "-"})

for k,v in d.items():
    F1 = F1.replace(v, k)

r = F1.split("+")
res = sum([i.split("*") for i in r], [])

result = []
for i in res:
    for k, v in d.items():
        if i.find(k) > -1:
            i = i.replace(k, v)
    result.append(i)
            
print(result)

"""--result
['A', 'x**3', 'B', 'cos(x+y)', 'C', 'exp(-x**2)', '-b', 'x', 'c', 'y']
"""

系数与项之间有什么？
A x3，上面的x前有两个星号，也不要了？

你题目的解答代码如下：

import re
F1='A*x**3+B*cos(x+y)+C*exp(-x**2)-b*x+c*y'
li = re.findall(r'(\-?[a-zA-Z]+\(.+?\)|\-?(?:\*\*|[a-zA-Z0-9])+)\*(\-?[a-zA-Z]+\(.+?\)|\-?(?:\*\*|[a-zA-Z0-9])+)',F1)
for a,b in li:
    print(a,b)

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