import pandas as pd
import numpy as np
df=pd.DataFrame({'a':[1,np.nan],
'b':['x',np.nan]})
s1=set(df['a'])
s2=set(df['b'])
s1.remove(np.nan)
s2.remove(np.nan)
print(s1,s2)
import pandas as pd
import numpy as np
import math
df=pd.DataFrame({'a':[1,np.nan],
'b':['x',np.nan]})
s1=set(df['a'])
s2=set(df['b'])
s1 = set([x for x in s1 if not math.isnan(x)])
print(s1)
集合用 .discard() 方法:
>>> import numpy as np
>>> np.nan
nan
>>> a = set([1,2,np.nan,3,4,np.nan,4,5])
>>> a
{nan, 1, 2, 3, 4, 5}
>>> a.discard(np.nan)
>>> a
{1, 2, 3, 4, 5}
s2测试了,也能通过的