Python计算机二级问题，望解答

题目:
学习语文时有中文重组句子，英语里也有重组句，定义一个函数 comb(sentence),其功能是把一英语句子的单词打乱，并把打乱的单词用一个空格连接起来，然后输出。如果句子的单词
小于等于 2 个就输出：原句的单词小于等于 2 个。（注意程序中的字符串全部使用双引号""表示）请把编号(1)~(7)和对应下划线删除，填空完成程序中的语句，不能修改已有的代码。
import random
def comb(sentence): #定义一个函数，参数为 sentence
words=(1)() #1 把单词分割出来
print("-"*60)
if len(words)==1 (2) len(words)==2: #2 如果句子中的单词小于 2 个，则不进行打乱，输出"
原句的单词小于等于 2 个"
print("原句的单词小于等于 2 个")
else:
jumble=[]
while (3): #3 对句子的单词进行打乱
site = (4)(len(words)) #4
jumble.(5)__ #5
words=_(6) #6 切片时位置如果是表达式要用括号()括起来
s=(7)(jumble) #7 把单词用一个空格连接起来
print("句子打乱顺序后的单词组合为:\n",s)
if name=="main":
txt="The Beijing Organising Committee for the 2022 Olympic and Paralympic Winter Games is a public institution with legal person status"
print("原句为:\n", txt)
comb(txt)

import random
def comb(sentence): #定义一个函数，参数为 sentence
    words=sentence.split() #1 把单词分割出来
    print("-"*60)
    if len(words)==1 or len(words)==2: #2 如果句子中的单词小于 2 个，则不进行打乱，输出"原句的单词小于等于 2 个"
        print("原句的单词小于等于 2 个")
    else:
        jumble=[]
        while (words): #3 对句子的单词进行打乱
            site = random.randrange(len(words)) #4
            jumble.append(words[site]) #5
            words=words[:(site)] + words[(site+1):] #6 切片时位置如果是表达式要用括号()括起来
        s=' '.join(jumble) #7 把单词用一个空格连接起来
        print("句子打乱顺序后的单词组合为:\n",s)

if __name__ == "__main__":
    txt="The Beijing Organising Committee for the 2022 Olympic and Paralympic Winter Games is a public institution with legal person status"
    print("原句为:\n", txt)
    comb(txt)

import random
def comb(sentence): #定义一个函数，参数为 sentence
    words=sentence.split()
    print("-"*60)
    if len(words)==1 or len(words)==2: #2 如果句子中的单词小于 2 个，则不进行打乱，输出"原句的单词小于等于 2 个"
        print("原句的单词小于等于 2 个")
    else:
        jumble=[]
        while len(words) != 0: #3 对句子的单词进行打乱
            site = random.randrange(len(words)) #4
            jumble.append(words[site])
            words= words[0:site] + words[site+1:]#6 切片时位置如果是表达式要用括号()括起来
        s=" ".join(jumble) #7 把单词用一个空格连接起来
        print("句子打乱顺序后的单词组合为:\n",s)
if __name__== "__main__":
    txt="The Beijing Organising Committee for the 2022 Olympic and Paralympic Winter Games is a public institution with legal person status"
    print("原句为:\n", txt)
    comb(txt)

import random

def comb(sentence): #定义一个函数，参数为 sentence
    words=sentence.split() #1 把单词分割出来
    print("-"*60)
    if len(words)==1 or len(words)==2: #2 如果句子中的单词小于 2 个，则不进行打乱，输出"原句的单词小于等于 2 个"
        print("原句的单词小于等于 2 个")
    else:
        jumble=[]
        while len(words)>0: #3 对句子的单词进行打乱
            site = random.choice(range(len(words))) #4
            jumble.append(words[site]) #5
            words=words[:site]+words[site+1:] #6 切片时位置如果是表达式要用括号()括起来
        s=' '.join(jumble) #7 把单词用一个空格连接起来
        print("句子打乱顺序后的单词组合为:\n",s)

if __name__=="__main__":
    txt="The Beijing Organising Committee for the 2022 Olympic and Paralympic Winter Games is a public institution with legal person status"
    print("原句为:\n", txt)
    comb(txt)

测试结果：

原句为:
 The Beijing Organising Committee for the 2022 Olympic and Paralympic Winter Games is a public institution with legal person status
------------------------------------------------------------句子打乱顺序后的单词组合为:
 with status Beijing Winter is Paralympic The Games 2022 person public for Organising a institution Olympic the legal Committee and