能不能尽早做出来，这个时间不多

编写程序，求1至1000以内同时被3和7整除的个数（要求用while循环实现）。


a = 1
count = 0
while a<=1000:
    if a%3 == 0 and a%7 == 0:
        count += 1
    a += 1
print(count)

n=1
count=0
while n<1000:
    if n%21==0:count+=1
    n+=1
print(count)

47个


num = 1
count = 0
while num != 1000:
    if num % 3 == 0 and num % 7 == 0:
        count += 1
        num += 1
    num += 1
print(count)

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count = 0
i = 1
while i<=1000:
    if i%3 == 0 and i%7 == 0:
        count += 1
    i += 1
print("同时被3和7整除的个数:",count,"个")

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