c/c++宏定义的问题

问题遇到的现象和发生背景

C/C++ 如何在预处理过程中宏定义N个0,；

问题相关代码，请勿粘贴截图

例如 #define LOOP_COUNTS(10) 0,0,0,0,0,0,0,0,0,0 这这样替换生成10个0,

运行结果及报错内容

例如我LOOP_COUNTS（5） 得到 0,0,0,0,0

我想要达到的结果

LOOP_COUNTS(N) ; 实现LOOP_COUNTS(N)替换N个0,...0;

为什么会有这么奇怪的需求？
不能换个思路处理你的问题嘛？
宏只替换不计算，无法实现你说的自动生成n个0
换个思路如果，n很小的话可以穷举
#define zn1 0
#define zn2 0,0
…
#define znn 0,0,0…0,0

亲测可以，希望采纳！

#include <stdio.h>

#define BOOST_PP_CAT(a, b) BOOST_PP_CAT_I(a, b)
#define BOOST_PP_CAT_I(a, b) BOOST_PP_CAT_II(~, a ## b)
#define BOOST_PP_CAT_II(p, res) res

#define BOOST_PP_NUM 1
#define BOOST_PP_ENUM_PARAMS(count, param) BOOST_PP_REPEAT(count, BOOST_PP_ENUM_PARAMS_M, param)
#define BOOST_PP_REPEAT BOOST_PP_CAT(BOOST_PP_REPEAT_,BOOST_PP_NUM)

#define BOOST_PP_REPEAT_1(c, m, d) BOOST_PP_REPEAT_1_I(c, m, d)
#define BOOST_PP_REPEAT_1_I(c, m, d) BOOST_PP_REPEAT_1_ ## c(m, d)
#define BOOST_PP_REPEAT_1_0(m, d)
#define BOOST_PP_REPEAT_1_1(m, d) m(2, 0, d)
#define BOOST_PP_REPEAT_1_2(m, d) BOOST_PP_REPEAT_1_1(m, d) m(2, 1, d)
#define BOOST_PP_REPEAT_1_3(m, d) BOOST_PP_REPEAT_1_2(m, d) m(2, 2, d)
#define BOOST_PP_REPEAT_1_4(m, d) BOOST_PP_REPEAT_1_3(m, d) m(2, 3, d)
#define BOOST_PP_REPEAT_1_5(m, d) BOOST_PP_REPEAT_1_4(m, d) m(2, 4, d)
#define BOOST_PP_REPEAT_1_6(m, d) BOOST_PP_REPEAT_1_5(m, d) m(2, 5, d)
#define BOOST_PP_REPEAT_1_7(m, d) BOOST_PP_REPEAT_1_6(m, d) m(2, 6, d)
#define BOOST_PP_REPEAT_1_8(m, d) BOOST_PP_REPEAT_1_7(m, d) m(2, 7, d)
#define BOOST_PP_REPEAT_1_9(m, d) BOOST_PP_REPEAT_1_8(m, d) m(2, 8, d)
#define BOOST_PP_REPEAT_1_10(m, d) BOOST_PP_REPEAT_1_9(m, d) m(2, 9, d)
#define BOOST_PP_REPEAT_1_11(m, d) BOOST_PP_REPEAT_1_10(m, d) m(2, 10, d)
#define BOOST_PP_REPEAT_1_12(m, d) BOOST_PP_REPEAT_1_11(m, d) m(2, 11, d)
#define BOOST_PP_REPEAT_1_13(m, d) BOOST_PP_REPEAT_1_12(m, d) m(2, 12, d)
#define BOOST_PP_REPEAT_1_14(m, d) BOOST_PP_REPEAT_1_13(m, d) m(2, 13, d)
#define BOOST_PP_REPEAT_1_15(m, d) BOOST_PP_REPEAT_1_14(m, d) m(2, 14, d)
#define BOOST_PP_REPEAT_1_16(m, d) BOOST_PP_REPEAT_1_15(m, d) m(2, 15, d)
#define BOOST_PP_REPEAT_1_17(m, d) BOOST_PP_REPEAT_1_16(m, d) m(2, 16, d)
#define BOOST_PP_REPEAT_1_18(m, d) BOOST_PP_REPEAT_1_17(m, d) m(2, 17, d)
#define BOOST_PP_REPEAT_1_19(m, d) BOOST_PP_REPEAT_1_18(m, d) m(2, 18, d)
#define BOOST_PP_REPEAT_1_20(m, d) BOOST_PP_REPEAT_1_19(m, d) m(2, 19, d)
#define BOOST_PP_REPEAT_1_21(m, d) BOOST_PP_REPEAT_1_20(m, d) m(2, 20, d)
#define BOOST_PP_REPEAT_1_22(m, d) BOOST_PP_REPEAT_1_21(m, d) m(2, 21, d)
#define BOOST_PP_REPEAT_1_23(m, d) BOOST_PP_REPEAT_1_22(m, d) m(2, 22, d)
#define BOOST_PP_REPEAT_1_24(m, d) BOOST_PP_REPEAT_1_23(m, d) m(2, 23, d)
#define BOOST_PP_REPEAT_1_25(m, d) BOOST_PP_REPEAT_1_24(m, d) m(2, 24, d)

//#define BOOST_PP_ENUM_PARAMS_M(z, n, param) BOOST_PP_COMMA_IF(n) param ## n
#define BOOST_PP_ENUM_PARAMS_M(z, n, param) BOOST_PP_COMMA_IF(n) param 

#define BOOST_PP_COMMA() ,
#define BOOST_PP_EMPTY()
#define BOOST_PP_COMMA_IF(cond) BOOST_PP_IF(cond, BOOST_PP_COMMA, BOOST_PP_EMPTY)()
#define BOOST_PP_IF(cond, t, f) BOOST_PP_IIF(BOOST_PP_BOOL(cond), t, f)
#define BOOST_PP_IIF(bit, t, f) BOOST_PP_IIF_I(bit, t, f)
#define BOOST_PP_IIF_I(bit, t, f) BOOST_PP_IIF_ ## bit(t, f)
#define BOOST_PP_IIF_0(t, f) f
#define BOOST_PP_IIF_1(t, f) t
#define BOOST_PP_BOOL(x) BOOST_PP_BOOL_I(x)
#define BOOST_PP_BOOL_I(x) BOOST_PP_BOOL_ ## x

#if 1
#define BOOST_PP_BOOL_0 0
#define BOOST_PP_BOOL_1 1
#define BOOST_PP_BOOL_2 1
#define BOOST_PP_BOOL_3 1
#define BOOST_PP_BOOL_4 1
#define BOOST_PP_BOOL_5 1
#define BOOST_PP_BOOL_6 1
#define BOOST_PP_BOOL_7 1
#define BOOST_PP_BOOL_8 1
#define BOOST_PP_BOOL_9 1
#define BOOST_PP_BOOL_10 1
#define BOOST_PP_BOOL_11 1
#define BOOST_PP_BOOL_12 1
#define BOOST_PP_BOOL_13 1
#define BOOST_PP_BOOL_14 1
#define BOOST_PP_BOOL_15 1
#define BOOST_PP_BOOL_16 1
#define BOOST_PP_BOOL_17 1
#define BOOST_PP_BOOL_18 1
#define BOOST_PP_BOOL_19 1
#define BOOST_PP_BOOL_20 1
#define BOOST_PP_BOOL_21 1
#define BOOST_PP_BOOL_22 1
#define BOOST_PP_BOOL_23 1
#define BOOST_PP_BOOL_24 1
#define BOOST_PP_BOOL_25 1
#endif


int  main()
{
    //test float num
    printf("a=%f, b=%f, c=%f, d=%f \n", BOOST_PP_ENUM_PARAMS(4,0.));

    //test int num
    printf("e=%d, f=%d, g=%d, h=%d, i=%d \n", BOOST_PP_ENUM_PARAMS(5,0));
    return 0;

}

要替换成的内容不要直接写N个0，改用一个循环就可以了

宏参数行不行，在什么情况下替换的

利用数字的初始化可以实现：

#include<stdio.h>
#define LOOP_COUNTS(N) int Zero[N]={0}

int main()
{
    LOOP_COUNTS(5);
    for (int i=0;i<5;i++)
        printf("%d ",Zero[i]);
    return 0;
}

你这个问题光用一个宏是无法实现的