例1:求f(x):=(x-2)+4在区间[-2,2]上的最小值。
一阶导数过后怎么比较区间上的正负
>>> fx = lambda x:(x-2)**2+4
>>> x = [x/10000 for x in range(-20000,20000+1)]
>>> y = [fx(i) for i in x]
>>> ymin = min(y)
>>> ymin
4.0
>>> xmin = x[y.index(ymin)]
>>> xmin
2.0
>>> # 当 x = 2.0 时,y最小值 = 4.0