明文和密文就想知道算法

Qo3eub%2BFCA%2BD9MTyndFTmw%3D%3D : 20708177

r3uwurYRCiuD9MTyndFTmw%3D%3D : 20707253

lPuTkNAljTuD9MTyndFTmw%3D%3D : 20708905

SwaFFDbYiQKD9MTyndFTmw%3D%3D : 20689076

VEyFL7oRmz%2BD9MTyndFTmw%3D%3D : 20708899

BM7djOprvIKD9MTyndFTmw%3D%3D : 20708900

VvmEpskR7wmD9MTyndFTmw%3D%3D : 20699121

F1nSfKJFOwWD9MTyndFTmw%3D%3D : 20683559

oKFwCOPuFuaD9MTyndFTmw%3D%3D : 20708936

1H6f47JGIWmD9MTyndFTmw%3D%3D : 20630100

GFtJPym0jmqD9MTyndFTmw%3D%3D : 20708935

kdW4y5c1TPGD9MTyndFTmw%3D%3D :20702685

QDSzMsxRabOD9MTyndFTmw%3D%3D :20708894

qfNNw0LAwLWD9MTyndFTmw%3D%3D :20702732

tE25svOzYXOD9MTyndFTmw%3D%3D :20708908

Ggef2qO9OrmD9MTyndFTmw%3D%3D :20708903

lh1YmvWu%2F%2FmD9MTyndFTmw%3D%3D :20708906

F1nSfKJFOwWD9MTyndFTmw%3D%3D :20683559

1H6f47JGIWmD9MTyndFTmw%3D%3D :20630100
jcIzVRkZDqGD9MTyndFTmw%3D%3D :20680037
Vm%2FquhhVtrWD9MTyndFTmw%3D%3D :20710189
wO%2F%2Ft1baM3%2BD9MTyndFTmw%3D%3D :20710207
i3gkfNFm1IyD9MTyndFTmw%3D%3D :20710187
NoczCRwY1sOD9MTyndFTmw%3D%3D :20710234
tZoMWsj%2BmrWD9MTyndFTmw%3D%3D :20710220
EyrBp7cbh9OD9MTyndFTmw%3D%3D :20710200
1e3Yx4RWjkSD9MTyndFTmw%3D%3D :20710190
Y6E0ekBHriqD9MTyndFTmw%3D%3D :20710193

%3D 是 URL 路径中的 = 的转义。这个 22 字节的密文,不太好知道加密算法。另外解密还必须有密钥才行。

你需要编写一些程序去跑这些字符来找到两者之间转换的密钥,复杂的密文你可能需要很大的算力才能够破解,算法是重点,建议楼主放弃。