这个的结果怎么求呢 想要一个详细过程

想要一个详细过程
怎么做呢
怎么做呢
想要一个详细过程
怎么做呢
怎么做呢

供参考：

//数组 c[] 记录数组 a[] 中 数值 < 60, 60 <= 数值 < 70, 70 <= 数值 < 90,90 <= 数值 < 101,各段数值元素的个数：

//c[0]：< 60
//c[1]：60 <= 数值 < 70
//c[2]：70 <= 数值 < 90
//c[3]：90 <= 数值 < 101

i = 0:
while (a[i=0] >= b[j=0]) j++;
a[i=0] = 76 ,b[j=0] = 60

while (a[i=0] >= b[j=1]) j++;
a[i=0] = 76 ,b[j=1] = 70

c[j=2] = 1

i = 1:
while (a[i=1] >= b[j=0]) j++;
a[i=1] = 63 ,b[j=0] = 60

c[j=1] = 1

i = 2:
c[j=0] = 1

i = 3:
while (a[i=3] >= b[j=0]) j++;
a[i=3] = 62 ,b[j=0] = 60

c[j=1] = 2

i = 4:
c[j=0] = 2

i = 5:
while (a[i=5] >= b[j=0]) j++;
a[i=5] = 75 ,b[j=0] = 60

while (a[i=5] >= b[j=1]) j++;
a[i=5] = 75 ,b[j=1] = 70

c[j=2] = 2

i = 6:
while (a[i=6] >= b[j=0]) j++;
a[i=6] = 80 ,b[j=0] = 60

while (a[i=6] >= b[j=1]) j++;
a[i=6] = 80 ,b[j=1] = 70

c[j=2] = 3

i = 7:
while (a[i=7] >= b[j=0]) j++;
a[i=7] = 92 ,b[j=0] = 60

while (a[i=7] >= b[j=1]) j++;
a[i=7] = 92 ,b[j=1] = 70

while (a[i=7] >= b[j=2]) j++;
a[i=7] = 92 ,b[j=2] = 90

c[j=3] = 1

i = 8:
while (a[i=8] >= b[j=0]) j++;
a[i=8] = 77 ,b[j=0] = 60

while (a[i=8] >= b[j=1]) j++;
a[i=8] = 77 ,b[j=1] = 70

c[j=2] = 4

i = 9:
while (a[i=9] >= b[j=0]) j++;
a[i=9] = 84 ,b[j=0] = 60

while (a[i=9] >= b[j=1]) j++;
a[i=9] = 84 ,b[j=1] = 70

c[j=2] = 5

i = 10:
c[j=0] = 3

i = 11:
while (a[i=11] >= b[j=0]) j++;
a[i=11] = 73 ,b[j=0] = 60

while (a[i=11] >= b[j=1]) j++;
a[i=11] = 73 ,b[j=1] = 70

c[j=2] = 6

最终结果：3261  ，c[0] = 3   c[1] = 2  c[2] = 6  c[3] = 1