s = [{'a':5},{'b':10},{'c':90},{'a':45},{'b':78},{'a':90},{'c':10}]
知道键是a
如何找出键为a 的索引
参考:
s = [{'a':5},{'b':10},{'c':90},{'a':45},{'b':78},{'a':90},{'c':10}]
key='a'
index = [i for i in range(len(s)) if key in s[i].keys()]
print(index)
s = [{'a':5},{'b':10},{'c':90},{'a':45},{'b':78},{'a':90},{'c':10}]
for i in s:
if 'a' in i:
print(s.index(i))
s = [{'a':5},{'b':10},{'c':90},{'a':45},{'b':78},{'a':90},{'c':10}]
key = "a"
#同时获取列表的索引和值
for index,value in enumerate(s):
if key in value.keys():
print(index)