这段代码为啥要输出两次

问题遇到的现象和发生背景

问题相关代码，请勿粘贴截图

运行结果及报错内容

我的解答思路和尝试过的方法

我想要达到的结果

prompt = "Please tell me something,and I will repeat it to you:\n"
prompt += "If you enter'quit',you will end the program.\n"
while True:
    if input(prompt) != 'quit':
        print(input(prompt))

    else:
        break

Please tell me something,and I will repeat it to you:
If you enter'quit',you will end the program.
a
Please tell me something,and I will repeat it to you:
If you enter'quit',you will end the program.
aa
aa
Please tell me something,and I will repeat it to you:
If you enter'quit',you will end the program.
s
Please tell me something,and I will repeat it to you:
If you enter'quit',you will end the program.
ss
ss
Please tell me something,and I will repeat it to you:
If you enter'quit',you will end the program.

print(input(prompt))
这是在玩啥呢
你前面不把input的内容先保存起来，后面print
而是用于判断是否是quit，后面用户必须再次输入一个内容，然后输出这个内容

prompt = "Please tell me something,and I will repeat it to you:\n"
prompt += "If you enter'quit',you will end the program.\n"
def a():
    while True:
        message = input(prompt)
        if message == 'quit':
            break
        print(message)
a()

这样就可以了，你看看有没有达到你的需求