在Javascript对象数组中查找值[重复]的并拿出每个对象中的ID


let arr = [{system:'ios',id:'1001',whether:true},{system:'linux',id:'1002',whether:false},{system:'win',id:'1003',whether:true}]

怎么才能从上面对象数组中把whether为true的id拿出来放到一个新的数组中结果为下面这样


let arr = ['1001', '1002' ,'1003' ]

filter然后map就行

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    let arr = [{ system: 'ios', id: '1001', whether: true }, { system: 'linux', id: '1002', whether: false }, { system: 'win', id: '1003', whether: true }]
    var ids = arr.filter(i => i.whether == true).map(i => i.id);
    alert(JSON.stringify(ids))

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有其他问题可以继续交流~

用forEach遍历，数组的内容是一个对象，判断成员whether

let arr = [{system:'ios',id:'1001',whether:true},{system:'linux',id:'1002',whether:false},{system:'win',id:'1003',whether:true}]

arr.forEach(item => {
    if (item.whether === true) {
         ....
    }
})


let newArr = arr.filter(o => o.whether == true).map(o => o.id);

let arr = [{system:'ios',id:'1001',whether:true},{system:'linux',id:'1002',whether:false},{system:'win',id:'1003',whether:true}]
let newarr = [];
arr.forEach(item=>{item.whether && newarr.push(item.id) })
console.log(newarr)

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对你有用的话，请点击一下【采纳此答案】，谢谢🌹

    const res = arr.reduce((cur, next) => {
        if (next.whether)
            cur.push(next.id)
        return cur
    }, [])
    console.log(res)

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