//这样可以嘛
#include <iostream>
using namespace std;
int main ()
{
double a = 0.0;
double sum = 0.0;
for (int i = 0; i < 4; i ++)
{
cin >> a;
sum += a;
}
double cnt = sum / 4;
cout << sum << endl << cnt << endl;
}
for(i=a;i<=d;i++)
if(i=a+b+c+d)
这写的是啥,直接
i=a+b+c+d;
后面分别输出i和i/4.0就行了
非要用循环?,那就用个数组来接收输入,然后循环加,再求平均。
float sum = 0;
sum += a;
sum += b;
sum += c;
sum += d;
float average = sum / 4;