使用char类型声明a~g,然后输出它们相加后的结果?
主要是设计ancii码的转换,最后结果是它们对应码的求和
char c[6] = ['a','b','c','d','e','f','g'];
int sum = 0;
for (int i = 0;i < 7;i++)
{
sum = sum + c[i];
}
printf("总和%d",sum);
int val = 0;
char[] vals = {'a', 'b', 'c', 'd', 'e', 'f', 'g'};
for (char c : vals)
val += (int)c;
System.out.println(val);
public class Test3 {
public static void main(String[] args) {
char[] c = {'a','b','c','d','e','f','g'};
int sum = 0;
for (int i = 0;i < 7;i++)
{
sum = sum + c[i];
}
System.out.println("总和:" + sum);
}
}