有一个题需要解答 求解

先定义一个点类point，包含数据成员x和y（坐标点）。以point类为基类，派生出矩形类Rectangle和圆类Circle。假设矩形水平放置，在Rectangle类中，继承来的基类中的点作为矩形左下方的顶点，在派生类中增加数据成员长和宽；在Circle类中，继承来的基类中的点作为圆点，在派生类中增加数据成员半径。
要求判断给定点位于矩形和圆的什么位置

#include <iostream>
using namespace std;
class point
{
public:
    float x;
    float y;

    point(float a = 0.0, float b = 0.0) : x(a), y(b) {}
    virtual void printLocation(point) { ; }
};

class Rectangle : public point
{
public:
    float width;
    float height;

    Rectangle(float x, float y, float w, float h)
        : point(x, y), width(w), height(h) {}
    void printLocation(point p)
    {
        if (p.x > this->x && p.y > this->y && p.x < this->x + width && p.y < this->y + height)
            cout << "Inside the rectangle\n";
        else if (p.x < this->x || p.y < this->y || p.x > this->x + width || p.y > this->y + height)
        {
            cout << "Outside the rectangle\n";
        }
        else
        {
            cout << "On the rectangular\n";
        }
    }
};

class Circle : public point
{
public:
    float radius;

    Circle(float x, float y, float r)
        : point(x, y), radius(r) {}

    void printLocation(point p)
    {
        float sqrdis = (p.x - this->x) * (p.y - this->y) + (p.y - this->y) * (p.y - this->y);
        if (sqrdis < radius * radius)
        {
            cout << "Inside the circle\n";
        }
        else if (sqrdis == radius * radius)
        {
            cout << "On the circle\n";
        }
        else
        {
            cout << "Outside the circle\n";
        }
    }
};

int main()
{
    Rectangle r(0, 0, 5, 5);
    r.printLocation(point(1, 2));  //Inside the rectangle
    r.printLocation(point(0, 4));  //On the rectangular
    r.printLocation(point(-1, 7)); //Outside the rectangle

    Circle c(0, 0, 1);
    c.printLocation(point(0, 1));      //On the circle
    c.printLocation(point(0.5, 0.25)); //Inside the circle
    c.printLocation(point(1, 1));      //Outside the circle
}

你看是不是要这样的