c++ itoa 不能用了，有什么能代替它吗

如题,itoa 不仅能把字符串转换成整型，还可以自选进制然后转换过去，实在太方便了，有什么可以替代吗？

自己写实现 给你个例子奥atoi

class Solution {
#define INT_MAX 2147483647
#define INT_MIN (-INT_MAX - 1)
public:
    // 是空格符
    bool isspace(char c)
    {
        return c == ' ' || c == '\r' || c == '\n' || c == '\t' || c == '\f' || c == '\b';
    }

    // 是数字 
    bool isdigit(char c)
    {
        return c >= '0' && c <= '9';
    }

    // 字符串转int数字
    int intatoi(string s)
    {
        int max[10] = {2,1,4,7,4,8,3,6,4,7};
        bool isoverflow = false;
        
        int result = 0;
        int count = 0;
        char sign = '+';
        
        while (isspace(s[count]))
        {
            count++;
        }
        
        if (s[count] == '-' || s[count] == '+')
        {
            sign = s[count];
            count++;
        }

        while(s[count] == '0')
        {
            count++;
        }

        int temp = count;
        int num = 0;
        while(isdigit(s[temp++]))
        {
            num++;
        }
        
        if (num == 10)
        {
            if (sign == '-')
            {
                max[9]++;
            }
            for (int i = 0; i < 10; i++)
            {
                if (s[count + i] - '0' > max[i])
                {
                    result = INT_MAX; 
                    isoverflow = true;
                    break;
                    if (sign == '-')
                    {
                        result = -result - 1;
                    }
                }
                else if (s[count + i] - '0' < max[i])
                {
                    isoverflow = false;
                    break;
                }
            }
        }
        if (num < 11 && !isoverflow)
        {
            while(isdigit(s[count]))
            {
                if (result == 214748364 && s[count] - '0' > 7 && sign == '-')
                {
                    return INT_MIN;
                }
                
                result = result * 10 + (s[count++] - '0');
            }
            if (sign == '-')
            {
                result = -result;
            }
        }
        else
        {
            result = INT_MAX; 
            if (sign == '-')
            {
                result = -result - 1;
            }
        }

        return result;
    } 

    int myAtoi(string s) {
        int result = intatoi(s);
        return result;
    }
};