关于#链表#的问题：下面代码运行时第一个员工的信息不能输出(语言-c++)

下面代码运行时第一个员工的信息不能输出，求解答！

#include<iostream>
#include<string.h>
using namespace std;
typedef struct EmpNode
{
    string category;
    string name;
    string sex;
    int age;
    int phone_number;
    struct EmpNode *next;
}Employee, *EmpPtr;
class EmpListLink
{
private:
    EmpPtr head;
    EmpPtr tail;
    int count;
public:
    EmpListLink(){};
    void CreateEmpList();
    void PrintEmpList();
};
void EmpListLink::CreateEmpList()
{
    EmpPtr p;
    cout<<"请输入员工的总数"<<endl;
    cin>>count;
    if(count<0)
    {
        cout<<"错误，总数应不小于0."<<endl;
        return ;
    }
    head=new Employee;
    head->age=0;
    head->category="0";
    head->name="0";
    head->phone_number=0;
    head->sex="0";
    head->next=NULL;
    tail=head;
    for(int i=0;i<count;i++)
    {
        p=new Employee;
        cout<<"请输入员工的姓名：";
        cin>>p->name;
        cout<<"请输入员工的性别：";
        cin>>p->sex;
        cout<<"请输入员工的年龄：";
        cin>>p->age;
        cout<<"请输入员工的电话号码：";
        cin>>p->phone_number;
        cout<<"请输入员工的类别：";
        cin>>p->category;
        p->next=NULL;
        tail->next=p;
        tail=p;
    }
    EmpPtr temp;
    temp=head->next;
    if(temp==NULL)
    {
        cout<<"学生链表为空！"<<endl;
        return ;
    }
    while(temp!=NULL)
    {
    cout<<p->name<<" "<<p->sex<<" "<<p->age<<" "<<p->phone_number<<" "<<p->category<<endl;
    temp=temp->next;
    }
}
int main()
{
    EmpListLink emplistlink;
    emplistlink. CreateEmpList();
    return 0;
}

temp=head->next;

你直接从第二个节点数出了啊

while(temp!=NULL)
 {
    cout<<p->name<<" "<<p->sex<<" "<<p->age<<" "<<p->phone_number<<" "<<p->category<<endl;
    temp=temp->next;
}

你用temp循环，为啥cout输出的是p的值呢？把p改成temp啊