老哥 圣诞树没居中在左上角而且比较小咋整呢 麻烦了谢谢您 自行车VB你们,asdfghjklzxcvbnm
帮题主用css调整了下大小,加了个点击页面后全屏展示的。大概下面这种效果
<!DOCTYPE HEML PUBLIC>
<html>
<head>
<meta charset="utf-8">
<style>
html, body {
width: 100%;
height: 100%;
margin: 0;
padding: 0;
border: 0;overflow:hidden
}
</style>
</head>
<body marginwidth="0" marginheight="0">
<div style="text-align: center; flex-direction: column; display: flex; width: 1000px; margin: 0 auto;">
<canvas id="c" height="356" width="446" style="height:1000px"></canvas>
</div>
<script>
var b = document.body;
var c = document.getElementsByTagName('canvas')[0];
var a = c.getContext('2d');
document.onclick = function () {
c.requestFullscreen();
}
</script>
<script>
M = Math;
Q = M.random; J = [];
U = 16;
T = M.sin;
E = M.sqrt;
for (O = k = 0; x = z = j = i = k < 200;)
with (M[k] = k ? c.cloneNode(0) : c) {
width = height = k ? 32 : W = 446;
with (getContext('2d'))
if (k > 10 | !k)
for (
font = '60px Impact',
V = 'rgba('; I = i * U, fillStyle = k ? k == 13 ? V + '205,205,215,.15)' :
V + (147 + I) + ',' + (k % 2 ? 128 + I : 0) + ',' + I + ',.5)' : '#cca', i < 7;
)
beginPath(
fill(
arc(
U - i / 3,
24 - i / 2,
k == 13 ? 4 - (i++) / 2 : 8 - i++,
0,
M.PI * 2, 1
)
)
);
else for (;
x = T(i),
y = Q() * 2 - 1,
D = x * x + y * y,
B = E(D - x / .9 - 1.5 * y + 1),
R = 67 * (B + 1) * (L = k / 9 + .8) >> 1,
i++ < W;
)
if (D < 1)
beginPath(
strokeStyle = V + R + ',' + (R + B * L >> 0) + ',40,.1)'
),
moveTo(U + x * 8, U + y * 8),
lineTo(U + x * U, U + y * U),
stroke();
for (
y = H = k + E(k++) * 25,
R = Q() * W;
P = 3, j < H;
)
J[O++] = [x += T(R) * P + Q() * 6 - 3, y += Q() * U - 8, z += T(R - 11) * P + Q() * 6 - 3, j / H * 20 + ((j += U) > H & Q() > .8 ? Q(P = 9) * 4 : 0) >> 1]
}
setInterval(function G(m, l) {
A = T(D - 11);
if (l)
return (
m[2] - l[2]) * A + (l[0] - m[0]) * T(D);
a.clearRect(0, 0, W, W);
J.sort(G);
for (
i = 0;
L = J[i++];
a.drawImage
(
M[L[3] + 1], 207 + L[0] * A + L[2] * T(D) >> 0, L[1] >> 1)) {
if (i == 2e3)
a.fillText
(
'Happy Christmas!',
U, 345);
if (!(i % 7))
a.drawImage
(
M[13],
((157 * (i * i) + T(D * 5 + i * i) * 5) % W) >> 0,
((113 * i + (D * i) / 60) % (290 + i / 99)) >> 0
);
}
D += .02
}, 1)
</script>
</body>
</html>
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