随机生成一个100元素列表

用random.randit（1，10）随机生成一个有100个元素的列表；定义一个函数，按列表元素出现次数的高低从高到底排序。

import random
countlist = []
for i in range(100):
    countlist.append(random.randint(1, 10))
dict = {}
for key in countlist:
    dict[key] = dict.get(key, 0) + 1
print(sorted(dict.items(), key=lambda kv: (kv[1], kv[0]), reverse=True))

from random import randint

list_n = []
flag = 0
while flag <= 99:
    n = randint(1,10)
    list_n.append(n)
    flag += 1
print(list_n)

def frequency_sort(items):
    # your code here
    lst1 = []
    for i in items:
        if i not in lst1:
            lst1.append(i)
    lst = []
    dic = {}
    # # print(lst1)
    for i in lst1:
        dic[i] = items.count(i)
    dic = dict(sorted(dic.items(), key=lambda x:x[1], reverse=True))
    # #print(dic)
    count = 0
    for k, v in dic.items():
        for i in range(v):
            lst.append(k)
    # # print(lst)
    return lst


if __name__ == '__main__':
    print("Example:")
    print(frequency_sort(list_n))