#python以下Symm(s)函数的功能是判定s是否为对称矩阵，若是返回True，否则返回False。在main()函数内输入一个矩阵以输入#结束调用Symm函数判定之。程序填空

def Symm(s):
    k=len(s)
    sy=  ____________________                                                
    return s==sy
def main():
    jz=[ ]
    while True:
        line=input()
        p=line.find("#")
        if p==-1:
            jz.append(list(map(float,line.split())))
        else:
            if p>0:
                jz.append(  ______________                               )
            break
    print(  _________________                                    )
if __name__=="__main__":
    main()

我想要达到的结果

def Symm(s):
    k = len(s)
    sy =[[s[j][i] for j in range(k)] for i in range(k)]
    return s == sy

def main():
    jz = []
    while True:
        line = input()
        p = line.find("#")
        if p == -1:
            jz.append(list(map(float, line.split())))
        else:
            if p > 0:
                jz.append(list(map(float, line[:-1].split())))
            break
    print(Symm(jz))

if __name__ == "__main__":
    main()

def Symm(s):
    k = len(s)
    sy= [[s[j][i] for j in range(k)] for i in range(k)]
    return s==sy
def main():
    jz=[ ]
    while True:
        line=input(">>>")
        p=line.find("#")
        if p==-1:
            jz.append(list(map(float,line.split())))
        else:
            if p>0:
                jz.append(list(map(float,line[:-1].split())))
            break
    print(Symm(jz))
if __name__=="__main__":
    main()