*abc12ababcab
输出:2
def cou(str1, str2):
len1 = len(str1)
len2 = len(str2)
count = 0
if len1 < len2:
str1, str2 = str2, str1
i = 0
while i <= len1 - len2:
j = 0
for _ in range(len2):
if str1[i+j] == str2[j]:
j += 1
if j ==len2:
count += 1
i += j
else:
i += 1
return count
res = cou('*abc12ababcab', 'abc')
print(res)