报错C2660 函数不接受1个参数

问题遇到的现象和发生背景

vs2019导入easyx包 但是在使用easyx的line 函数却出现了c2660报错

问题相关代码,请勿粘贴截图
#include <iostream>
#include <easyx.h>
#include <conio.h>

using namespace std;
void Init();
void changeX();
void changeY();

//倍数
const int mulx = 60;
const int muly = 60;

//坐标中心点       
const int X = 100;
const int Y = 300;

int main()
{
    Init();
    return 0;
}


//sinx / x
void Sin()
{
    setlinecolor(BLACK);
    double t1 = changeX(0), t2 = changeY(1);
    for (double i = 0.1; i <= 6; i += 0.1)
    {
        line((int)t1, (int)t2, (int)changeX(i), (int)changeY(sin(i) / i));
        t1 = changeX(i);
        t2 = changeY(sin(i) / i);
    }

}

void StepIntegration()
{
    setlinecolor(BLUE);
    double a = 0, b = 6, e = 1e-5;
    double h = b - a;
    double T1 = h / 2 * (1 - sin(b) / b), T2 = 0;
    double S, x;
    S = 0;
    x = a + h / 2;

    while (true)
    {
        //S = 0;
        //x = a = h / 2;


        line(changeX(x), changeY(sin(x) / x), changeX(x), changeY(0));

        S += (sin(x) / x);
        x += h;

        if (x >= b)
        {
            T2 = T1 / 2 + h / 2 * S;

            if (fabs(T2 - T1) < e)
            {
                char t[10];
                _gcvt_s(t, 10, T2, 8);
                outtextxy(150, 100, t);
                break;
            }
            else
            {

                h /= 2;
                T1 = T2;

                S = 0;
                x = a + h / 2;
            }
        }

    }

}

void Longberg()
{
    double a = 0, b = 6, e = 1e-5;
    int k = 1;
    double h = b - a;
    double T1 = h / 2 * (1 - sin(b) / b), T2 = 0;
    double S = 0, x = 0;
    double C1 = 0, C2 = 0, R2 = 0, R1 = 0, S2 = 0, S1 = 0;

    S = 0;
    x = a + h / 2;

    while (true)
    {
        line(changeX(x), changeY(sin(x) / x), changeX(x), changeY(0));

        S += (sin(x) / x);
        x += h;

        if (x >= b)
        {

            T2 = T1 / 2 + h / 2 * S;
            S2 = T2 + 1.0 / 3.0 * (T2 - T1);

            if (k != 1)
            {
                C2 = S2 + (1.0 / 15.0) * (S2 - S1);

                if (k != 2)
                {

                    R2 = C2 + (1.0 / 63.0) * (C2 - C1);

                    if (k != 3)
                    {

                        if (fabs(R2 - R1) < e)
                        {
                            char f[20];
                            _gcvt_s(f, 20, R2, 8);
                            outtextxy(320, 100, f);
                            break;
                        }
                        else
                        {
                            R1 = R2;

                            C1 = C2;
                            k++;
                            h /= 2;
                            T1 = T2;
                            S1 = S2;

                            S = 0;
                            x = a + h / 2;
                        } //fabs
                    }
                    else {
                        R1 = R2;

                        C1 = C2;
                        k++;
                        h /= 2;
                        T1 = T2;
                        S1 = S2;

                        S = 0;
                        x = a + h / 2;
                    }//k!=3
                }
                else
                {
                    C1 = C2;
                    k++;
                    h /= 2;
                    T1 = T2;
                    S1 = S2;

                    S = 0;
                    x = a + h / 2;
                }//k!=2
            }
            else
            {
                k += 1;
                h /= 2;
                T1 = T2;

                S1 = S2;

                S = 0;
                x = a + h / 2;
            }//k!=1
        }

    }
}

double changeX(double x)
{
    return X + mulx * x;
}

double changeY(double y)
{
    return Y - 2.0 * muly * y;
}


void Axis()
{
    setlinecolor(BLACK);

    //x轴  及其箭头
    line(X - 50, Y, mulx * 6 + X + 30, Y);
    line(mulx * 6 + X + 15, Y - 15, mulx * 6 + X + 30, Y);
    line(mulx * 6 + X + 15, Y + 15, mulx * 6 + X + 30, Y);

    //y轴
    line(X, Y + 70, X, Y - 3 * muly - 40);
    line(X - 15, Y - 3 * muly - 25, X, Y - 3 * muly - 40);
    line(X + 15, Y - 3 * muly - 25, X, Y - 3 * muly - 40);


    settextcolor(BLACK);
    outtextxy(X - 10, Y + 10, "O");


    char s[10];
    //x轴刻度
    for (int i = 1; i <= 6; ++i)
    {
        line((int)(X + i * mulx), (int)Y, (int)(X + i * mulx), (int)(Y - 3));
        _gcvt_s(s, 10, i * 1.00, 3);
        outtextxy(X + i * mulx - 3, Y + 3, s);
    }
    //y轴刻度
    //double t = 0.5;
    for (int i = 1; i <= 3; ++i)
    {
        line((int)X, (int)(Y - i * muly), (int)(X + 3), (int)(Y - i * muly));
        _gcvt_s(s, 10, i * 0.5, 3);
        outtextxy(X - 20, Y - i * muly - 8, s);
    }

}

//按钮
void Button()
{
    //x ,  y  为左上角点的位置
    setlinecolor(BLACK);
    settextcolor(BLACK);
    //矩形的长度和高度
    int l = 120, h = 40;

    int r1[] = { 120,50 };
    int r2[] = { 300,50 };

    setbkmode(TRANSPARENT);

    roundrect(r1[0], r1[1], r1[0] + l, r1[1] + h, 20, 20);
    char strtemp[] = "StepIntegration";
    int w = textwidth(strtemp);
    int h1 = textheight(strtemp);
    outtextxy(r1[0] + (l - w) / 2, r1[1] + (h - h1) / 2, strtemp);

    roundrect(r2[0], r2[1], r2[0] + l, r2[1] + h, 20, 20);
    char strtemp1[] = "Longberg";
    w = textwidth(strtemp1);
    h1 = textheight(strtemp1);
    outtextxy(r2[0] + (l - w) / 2, r2[1] + (h - h1) / 2, strtemp1);


    ExMessage msg;
    while (true)
    {
        while (peekmessage(&msg, EM_MOUSE))
        {
            //"StepIntegration"
            if (msg.x > r1[0] && msg.x<r1[0] + l && msg.y>r1[1] && msg.y < r1[1] + h)
            {
                setfillcolor(RED);
                floodfill(r1[0] + 5, r1[1] + 5, BLACK);
                if (msg.message == WM_LBUTTONDOWN)
                {
                    StepIntegration();
                }
            }
            else {
                setfillcolor(WHITE);
                floodfill(r1[0] + 5, r1[1] + 5, BLACK);
            }

            //"Longberg"
            if (msg.x > r2[0] && msg.x<r2[0] + l && msg.y>r2[1] && msg.y < r2[1] + h)
            {
                setfillcolor(RED);
                floodfill(r2[0] + 5, r2[1] + 5, BLACK);
                if (msg.message == WM_LBUTTONDOWN)
                {
                    Longberg();
                }
                //Sleep(20);
            }
            else {
                setfillcolor(WHITE);
                floodfill(r2[0] + 5, r2[1] + 5, BLACK);
            }
        }
    }
}

void Init()
{
    initgraph(540, 460, EW_SHOWCONSOLE);
    setbkcolor(WHITE);
    cleardevice();
    setlinecolor(BLACK);

    Axis();
    Sin();
    Button();
    _getch();
    closegraph();

运行结果及报错内容
我的解答思路和尝试过的方法
我想要达到的结果