package servletdemo01;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class ServletDemo01 extends HttpServlet{
@Override
protected void doGet(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
System.out.println("-----doGet--------");
}
@Override
protected void doPost(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
System.out.println("-----doPost--------");
}
}
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://JAVA.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<display-name>ServletDemo01</display-name>
<servlet>
<servlet-name>ServletDemo01</servlet-name>
<servlet-calss>servletdemo01.ServletDemo01</servlet-calss>
</servlet>
<servlet-mapping>
<servlet-name>ServletDemo01</servlet-name>
<url-pattern>/demo</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>
</web-app>
怎么解决啊?
访问路劲不对啊,好得写个html页面啊
访问路径应该是访问Servlet的,你这个路径是web.xml文件的路径。按你配置文件里的配置,访问路径应该写:
http://localhost:8080/ServletDemo01/demo
ServletDemo01是你的项目名,也叫项目的虚拟路径,demo是Servlet文件的虚拟路径,就是web.xml文件里url-pattern标签里的数据。