输入三行文本每行最多100个字符，计算三行文本字母数并输出结果，在两列中显示结果，无需处理特殊字符，基本字母即可，具体样例如下

Give a string (max 100 characters) > Hello World
Give a string (max 100 characters) > It is a nice day
Give a string (max 100 characters) > Hope you are fine
Alphabet Count
a 3
b 0
c 1
d 2
e 5
f 1
g 0
h 2
i 4
j 0
k 0
l 3
m 0
n 2
o 4
p 1
q 0
r 2
s 1
t 1
u 1
v 0
w 1
x 0
y 2
z 0

#include <stdio.h>
int main()
{
    char str[3][101];
    int i,j;
    int sum[26];
    for(i=0;i<26;i++)
        sum[i]=0;
    for (i=0;i<3;i++)
    {
        printf("Give a string (max 100 characters) > ");
        gets(str[i]);
    }
    for (i=0;i<3;i++)
    {
        j=0;
        while(str[i][j])
        {
            if(str[i][j]>='a' && str[i][j]<='z')
                sum[str[i][j]-'a']++;
            else if(str[i][j]>='A' && str[i][j]<='Z')
                sum[str[i][j]-'A']++;
            j++;
        }
    }
    for (i=0;i<26;i++)
    {
        printf("%c %d\n",'a'+i,sum[i]);
    }
    return 0;
}

能存活么。兄弟你加点自己的思考吧

#include <stdio.h>
int main()
{
    char s[110];
    int k=3;
    char c[26]={0};
    while(k--){
        printf("Give a string (max 100 characters) > ");
        gets(s);
        for(int i=0;s[i]!='\0';i++){
            if(s[i]>='A'&&s[i]<='Z'){
                c[s[i]-'A']++;
            }
            else if(s[i]>='a'&&s[i]<='z'){
                printf("%c\t\t%d\n",s[i], c[s[i]-'a']);
                c[s[i]-'a']++;
            }
        }
    }
    printf("Alphabet\tCount\n");
    for(int i=0;i<26;i++){
        printf("%c\t\t%d\n",'a'+i, c[i]);
    }
    return 0;
}