结构体与指针实现链表的创建和遍历

输入a,b,c,d,e,f六个字符作为结点的数据，创建具有六个数据元素的链表，然后实现输出链表结点中的数据元素值。要求有交互界面，输入1为创建链表，输入0为退出程序，输入2为显示链表中的数据元素

代码如下：

#include <iostream>
using namespace std;


typedef struct Node 
{
    char c;
    struct Node* next;
};
//创建链表
struct Node* createList()
{
    int i,n;
    char ch;
    struct Node* head,*p,*t;
    head = new Node;
    head->next = NULL;
    p = head;
    n = 6;
    cout << "请输入6个字符：";
    for (i=0;i<n;i++)
    {
        t = new Node;
        cin >> t->c ;
        t->next = NULL;
        p->next = t;
        p = t;
    }
    return head;
}

//显示链表
void printList(struct Node* head)
{
    struct Node* p;
    if(head == NULL) return;
    p = head->next;
    while(p)
    {
        cout << p->c <<  endl;
        p = p->next;
    }
}




int main()
{
    int opt;
    char ch;
    struct Node* head = 0;
    
    while(1)
    {
        cout << "1.创建链表"<<endl;
        cout << "2.显示链表"<<endl;
        cout << "0.退出"<<endl;
        cin >> opt;
        
        switch(opt)
        {
        case 1:
            head = createList();
            cout << "链表创建成功"<< endl;

            break;
        case 2:
            if(head == 0)
                cout <<"链表为空"<<endl;
            else
                printList(head);
            break;
        case 0:
            return 0;
        }
    }
    

    return 0;
}