python求列表中后一个数是前一个数的两倍的数
def doubles(l):
for i,v in enumerate(l[1:], 1):
if v ==2 * l[i-1]:
print(v)
def main():
mylist = [3, 0, 1, 2, 3, 6, 2, 4, 5, 6, 12]
doubles(mylist)
main()
def doubles(l):
for i,v in enumerate(l[1:], 1):
if v ==2 * l[i-1]:
print(v)
def main():
mylist = [3, 0, 1, 2, 3, 6, 2, 4, 5, 6, 12]
doubles(mylist)
main()