Python 求n!／（m!（n－m）!）

Python 求n!／（m!（n－m）!），其中求阶乘的操作用自函数实现

def jc( n):
    b = 1
    for i in range(1,n+1):
        b = b*i
    return b
n = int(input())
m = int(input())
k = jc(n)/(jc(m)*jc(n-m))
print(k)

def fun(a):
    sum = 1
    for i in range(a + 1):
        sum *= i + 1
    return sum

n = 5
m = 6

print(fun(n) / (fun(m) fun(n - m)))