如何实现字符等于字符

你题目的解答代码如下：

#include<stdio.h>
int main() {
    int n,m;
    char c;
    double t,p;
    scanf("%d %d %c",&n,&m,&c);
    p = (c=='a') ? 0.95 : 0.98;
    switch(m) {
        case 89: t = 6.17; break;
        case 92: t = 5.58; break;
        case 95: t = 5.96; break;
    }
    printf("%.2lf",n*t*p);
    return 0;
}

如有帮助，望采纳！谢谢!