望各位帮忙看看，现在就想要答案，蟹蟹各位潜水专家，感谢解答，感谢回答，感谢解答。编写一个 MIPS 汇编程序，相当于这个 C 程序：在原有的基础上完成这个程序。我需要答案，我想要的是直接把代码告诉我
// read a line from stdin and and then an integer n
// Print the character in the nth-position
#include <stdio.h>
// line of input stored here
char line[256];
int main(void) {
printf("Enter a line of input: ");
fgets(line, 256, stdin);
printf("Enter a position: ");
int n;
scanf("%d", &n);
printf("Character is: ");
printf("%c", line[n]);
printf("%c", '\n');
return 0;
}
# read a line from stdin and and then an integer n
# Print the character in the nth-position
# n in $t0
main:
la $a0, str0 # printf("Enter a line of input: ");
li $v0, 4
syscall
la $a0, line # fgets(buffer, 256, stdin)
la $a1, 256
li $v0, 8
syscall
la $a0, str1 # printf("Enter a position: ");
li $v0, 4
syscall
li $v0, 5 # scanf("%d");
syscall
move $t0, $v0
la $a0, str2 # printf("Character is: ");
li $v0, 4
syscall
li $a0, '?' # printf("%c", '?');
li $v0, 11
syscall
li $a0, '\n' # printf("%c", '\n');
li $v0, 11
syscall
li $v0, 0 # return 0
jr $ra
.data
str0:
.asciiz "Enter a line of input: "
str1:
.asciiz "Enter a position: "
str2:
.asciiz "Character is: "
# line of input stored here
line:
.space 256
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