#include <stdio.h>
#include <stdlib.h>
#include <windows.h>
int main ()
{
int one,two,three,four1,four2,five;
four1=0;
four2=0;
for(one=4;one<=100;one+=2)
{
for(two=2;two<=one/2;two++)
{
for(three=2;three<one-1;three++)
{
if(one%three==0)
{
four1++;
break;
}
//if(four==0)
//{
five=one-two;
if(five%three==0)
{
four2++;
break;
}
//if(four1==0||four2==0)
//printf("%d=%d+%d",one,two,five);
//if(four=0)
//printf("%d=%d+%d",one,two,one);
}
}
}
if(four1==0||four2==0)
printf("%d=%d+%d",one,two,five);
}
return 0;
}
多了一个}
把35行的}或者40行的}删掉,删哪个看你的逻辑
return 0; 移到上一个大括号里面去。并把42行的}删除。
多写了一层大括号
修改后代码如下
有帮助望采纳~
#include <stdio.h>
#include <stdlib.h>
#include <windows.h>
int main()
{
int one, two, three, four1, four2, five;
four1 = 0;
four2 = 0;
for (one = 4; one <= 100; one += 2)
{
for (two = 2; two <= one / 2; two++)
{
for (three = 2; three < one - 1; three++)
{
if (one % three == 0)
{
four1++;
break;
}
//if(four==0)
//{
five = one - two;
if (five % three == 0)
{
four2++;
break;
}
//if(four1==0||four2==0)
//printf("%d=%d+%d",one,two,five);
//if(four=0)
//printf("%d=%d+%d",one,two,one);
}
}
}
if (four1 == 0 || four2 == 0)
printf("%d=%d+%d", one, two, five);
return 0;
}