js如何筛选出两组数据中的某个属性里面相等的值

比如数据格式如下

let arr1 = [
    {
        "specName": "颜色",
        "specItems": [
            {
                "specItem": "黄色",
                "image": ""
            },
            {
                "specItem": "白色",
                "image": ""
            },
            {
                "specItem": "红色",
                "image": ""
            }
        ],
        "productspecId": "2490ad9e-96b5-4bcd-a846-076c097b2eec",
        "value": "attributeName1",
        "isCheck": false
    },
    
]
let arr2 = [
    {
        "value": "黄色",
        "checked": false
    },
    {
        "value": "白色",
        "checked": false
    },
    {
        "value": "红色",
        "checked": false
    },
    {
        "value": "紫色",
        "checked": false
    }
]

我想比较arr1中specItems里面每一个specItem和arr2中每一个value相不相等并把其中相等的arr2对应的checked变成true,求详细解释

 let newArray = []
          for (let i = 0; i < this.tableCategoryList.length; i++) {
            const element =  this.tableCategoryList[this.clickProducIndex].specItems;
            for (let o = 0; o <  this.dynamicTags.length; o++) {
              const element2 =  this.dynamicTags[o].value;
              if (element == element2 ) {
                console.log(true)
              
              }else{
                console.log('false')
              }
            }
          }

这是我写的，只比较出了两个值相不相等

是一对一吗？

    const { specItems } = arr1[0];
    arr2.forEach((cur, index) => {
      specItems[index] && cur.value === specItems[index].specItem
        ? (cur.checked = true)
        : null;
    });
    console.log(arr1, arr2);

arr2.forEach(v=>{arr1[0].specItems.find(v1=>{if(v1.specItem===v.value){v.checked=true;}})})