C语言Building an Array，九九我吧

请问这个应该怎么做？要求需要使用 malloc 和 free。第一，二张是要求，第三张是机翻。求大lao忙帮，蟹蟹。

#include <stdio.h>

#define SIZE 3

void printArray(int **arr);

int main(int argc, char *argv[]) {

    // TODO BELOW
    //  part1: ensure the right number of arguments have been passed in
    // TODO ABOVE

    // TODO BELOW
    //  part2: ensure the argument we're interested is in of right length
    // TODO ABOVE

    // TODO BELOW
    //  part3: malloc your 2D array and populate it
    // TODO ABOVE

    printArray(myArray);
    free(myArray);

    return 0;
}

void printArray(int **arr) {
    int i = 0;
    int j = 0;
    while (i < SIZE) {
        j = 0;
        while (j < SIZE) {
            printf("%d ", arr[i][j]);
            j++;
        }
        printf("\n");
        i++;
    }
}

代码如下：如有帮助，请采纳一下，谢谢。

#include <stdio.h>
#include <stdlib.h>
#define SIZE 3
void printArray(int **arr);
int main(int argc, char *argv[]) {
    // TODO BELOW
    //  part1: ensure the right number of arguments have been passed in
    if(argc < 2)
        return 0;
    // TODO ABOVE
    // TODO BELOW
    //  part2: ensure the argument we're interested is in of right length
    int len = 0;
    while(argv[1][len] != '\0')
        len++;
    if(len != 9)
    {
        printf("length < 9,please input the right numbers\n");
        return 0;
    }
    // TODO ABOVE
    // TODO BELOW
    //  part3: malloc your 2D array and populate it
    int **myArray = (int**)malloc(SIZE * sizeof(int*));
    for(int i = 0;i<SIZE;i++)
    {
        myArray[i] = (int*)malloc(SIZE * sizeof(int) );
        for(int j = 0;j<SIZE;j++)
            myArray[i][j] = (int)(argv[1][i*3+j] - '0');
    }
    // TODO ABOVE
    printArray(myArray);
    free(myArray);
    return 0;
}
void printArray(int **arr) {
    int i = 0;
    int j = 0;
    while (i < SIZE) {
        j = 0;
        while (j < SIZE) {
            printf("%d ", arr[i][j]);
            j++;
        }
        printf("\n");
        i++;
    }
}