1000以内能同时被6和8整除的前三个数，用break

l = [];
index = 0;
for item in range(1, 1000):
    if item % 6 == 0 and item % 8 == 0:
        if index == 3:
            break;
        else:
            index += 1;
            l.append(item)
print(l)