编写函数fun求1的k次方到N的k次方的累加和

long fun(int n, int k)
{
	long int sum = 0,temp;
	for (int i = 1; i <= n; i++)
	{
            temp =i;
		for (int j = 1; j < k; j++)
			temp *= i;
		sum += temp;
	}
	return sum;
}

int fun(int n,int k)
{
	int i,j;
	int sum = 0;
	int temp = 1;
	for (i = 1; i <= n; i++)
	{
		for (j = 0; j < k; j++)
		{
			temp *= i;
		}
		sum += temp;
		temp = 1;
	}
	return sum;
}