求C语言题目！谢谢

求C语言题目！谢谢

思路大概这样吧，纯手打没调试过，有报错的修复一下。

 

#include <stdbool.h>
#include <stdint.h>
#include <stdlib.h>
#include <math.h>

typedef struct
{
  char strProvince[2];    //省份编号
  char strCity[2];        //地市编号
  char strCounty[2];      //区县编号
  char strYear[4];        //出生年份
  char strMonth[2];       //出生月份
  char strDay[2];         //出生日子
  char strGender[3];      //性别
  char strCRC[1];         //校验
  char strEOF[1];         //结束符
}T_PERSON_ID;


char strPerson_ID[18] = {"11010219650321XXXX\0"};


void main()
{
    uint8_t i_scan = 0;

    uint8_t len_temp = 0;

    int16_t result_year = -1;         //出生年份
    int8_t result_month = -1;         //出生月份
    int8_t result_day = -1;           //出生日子

    int16_t result_gender = -1;       //性别（男：0；女:1）


    T_PERSON_ID *ppreson_id = NULL;


    /* 指针重指向 */
    ppreson_id = (T_PERSON_ID *)strPerson_ID;


    #if 1    //atoi方式

    /** 出生年月 ***************************************************************/

    result_year = atoi(ppreson_id->strYear);
    result_month = atoi(ppreson_id->strMonth);
    result_day = atoi(ppreson_id->strDay);


    /** 性别 ******************************************************************/

    result_gender = (atoi(ppreson_id->strDay) % 2) ? 0 : 1;

    #else    //非atoi方式


    /** 出生年月 ***************************************************************/    

    len_temp = sizeof(ppreson->strYear)
    for(i_scan = 0; i_scan < len_temp; i_scan++)
    {
        result_year += (ppreson->strYear[i_scan] - '0') * pow(10, len_temp - i_scan - 1);
    }
    
    len_temp = sizeof(ppreson->strMonth)
    for(i_scan = 0; i_scan < len_temp; i_scan++)
    {
        result_month += (ppreson->strMonth[i_scan] - '0') * pow(10, len_temp - i_scan - 1);
    }
    
    len_temp = sizeof(ppreson->strDay)
    for(i_scan = 0; i_scan < len_temp; i_scan++)
    {
        result_day += (ppreson->strDay[i_scan] - '0') * pow(10, len_temp - i_scan - 1);
    }


    /** 性别 ******************************************************************/

    len_temp = sizeof(ppreson->strGender)
    for(i_scan = 0; i_scan < len_temp; i_scan++)
    {
        result_gender += (ppreson->strGender[i_scan] - '0') * pow(10, len_temp - i_scan - 1);
    } 
    result_gender = (result_gender_man % 2) ? 0 : 1;

    #endif
}