<?
$pic = "[pic]";
ob_start();
echo $pic;
$str = ob_get_contents();
ob_end_clean();
echo $str;
echo '<img src="'.htmlspecialchars(phpThumbURL('src='.$str.'&w=300', '/Thumb/thumbs.php')).'">';
?>
执行出来就是不对
echo $str;为
upload/1.jpg
upload/2.jpg
upload/3.jpg
echo '<img src="'.htmlspecialchars(phpThumbURL('src='.$str.'&h=342', '/Thumb/thumbs.php')).'">';为
<img src="/Thumb/thumbs.php?src=%3Apic%5D&w=300 ">
<img src="/Thumb/thumbs.php?src=%3Apic%5D&w=300">
<img src="/Thumb/thumbs.php?src=%3Apic%5D&w=300">
求解答
你代码发全了?$echo $str;应该是输出[pic]吧..怎么有图片路径