JS怎么计算两条线相交点的经纬度？

已知两条线

已知四个点的经纬度（假设相交的情况）该如何计算他们相交点的经纬度？

https://blog.csdn.net/hf872914334/article/details/111590098

/* 
* 线段与线段的交点
* 解线性方程组, 求线段AB与线段CD的交点坐标，如果没有交点，返回null
*/
function intersects(coords1, coords2) {
  let x1 = coords1[0][0];
  let y1 = coords1[0][1];
  let x2 = coords1[1][0];
  let y2 = coords1[1][1];
  let x3 = coords2[0][0];
  let y3 = coords2[0][1];
  let x4 = coords2[1][0];
  let y4 = coords2[1][1];
  //斜率交叉相乘 k1 = (y4 - y3) / (x4 - x3)    k2 = (y2 - y1) / (x2 - x1)
  //k1 k2 同乘 (x4 - x3) * (x2 - x1) 并相减得到denom
  let denom = ((y4 - y3) * (x2 - x1)) - ((x4 - x3) * (y2 - y1)); 
  // 如果分母为0 则平行或共线, 不相交 
  if (denom === 0) {
    return null;
  }

  let numeA = ((x4 - x3) * (y1 - y3)) - ((y4 - y3) * (x1 - x3));
  let numeB = ((x2 - x1) * (y1 - y3)) - ((y2 - y1) * (x1 - x3));
  let uA = numeA / denom;
  let uB = numeB / denom;

  // 交点在线段1上，且交点也在线段2上  
  if (uA >= 0 && uA <= 1 && uB >= 0 && uB <= 1) {
    let x = x1 + (uA * (x2 - x1));
    let y = y1 + (uA * (y2 - y1));
    return [x, y];
  }
  return null;
}
intersects([[0,0],[1,1]], [[3,0],[2,1]])  //null
intersects([[0,0],[1,1]], [[3,0],[0,1]])  //[0.75, 0.75]

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这个算起来很麻烦

<!DOCTYPE html>
<html>
	<head>
		<meta charset="utf-8">
		<title></title>
	</head>
	<body>
		<script type="text/javascript">
			/*
			 **函数 取点1点2连线与点3点4连线交点(点1经度,点1纬度,点2经度,点2纬度,点3经度,点3纬度,点4经度,点4纬度,)
			 **返回 交点经纬度
			 */
			function getPoint(jd1, wd1, jd2, wd2, jd3, wd3, jd4, wd4) {
				var j1, j2, j3, j4, w1, w2, w3, w4, x1, x2, x3, x4, y1, y2, y3, y4, z1, z2, z3, z4, a1, a2, b1, b2, c1, c2;
				j1 = jd1 * Math.PI / 180;
				j2 = jd2 * Math.PI / 180;
				j3 = jd3 * Math.PI / 180;
				j4 = jd4 * Math.PI / 180;
				w1 = wd1 * Math.PI / 180;
				w2 = wd2 * Math.PI / 180;
				w3 = wd3 * Math.PI / 180;
				w4 = wd4 * Math.PI / 180;
				x1 = Math.cos(j1) * Math.cos(w1);
				x2 = Math.cos(j2) * Math.cos(w2);
				x3 = Math.cos(j3) * Math.cos(w3);
				x4 = Math.cos(j4) * Math.cos(w4);
				y1 = Math.sin(j1) * Math.cos(w1);
				y2 = Math.sin(j2) * Math.cos(w2);
				y3 = Math.sin(j3) * Math.cos(w3);
				y4 = Math.sin(j4) * Math.cos(w4);
				z1 = Math.sin(w1);
				z2 = Math.sin(w2);
				z3 = Math.sin(w3);
				z4 = Math.sin(w4);
				a1 = y1 * z2 - y2 * z1;
				a2 = y3 * z4 - y4 * z3;
				b1 = z1 * x2 - z2 * x1;
				b2 = z3 * x4 - z4 * x3;
				c1 = x1 * y2 - x2 * y1;
				c2 = x3 * y4 - x4 * y3;
				var dx5, y5, z5;
				x5 = b1 * c2 - b2 * c1;
				y5 = c1 * a2 - c2 * a1;
				z5 = a1 * b2 - a2 * b1;
				var da, db;
				da = Math.atan2(y5, x5);
				db = Math.asin(z5 / Math.pow(Math.pow(x5, 2) + Math.pow(y5, 2) + Math.pow(z5, 2), 0.5));
				if (Math.abs(da - j1) > Math.PI || Math.abs(da - j2) > Math.PI || Math.abs(da - j3) > Math.PI || Math.abs(da - j4) >
					Math.PI || Math.abs(db - w1) > Math.PI || Math.abs(db - w2) > Math.PI || Math.abs(db - w3) > Math.PI || Math.abs(
						db - w4) > Math.PI) {
					if (da > 0) {
						da -= Math.PI;
					} else {
						da += Math.PI;
					}
					db = -db;
				}
				return {
					jd: da * 180 / Math.PI,
					wd: db * 180 / Math.PI
				};
			}
			console.log(getPoint(0, 0, 0, 90, 20, 10, -20, 10));
		</script>
	</body>
</html>