quarterIdThe = params[:quarterThe_id].to_s #得到--本季度操作--对话框

department = params[:department_id] #得到选择的部门名称
upThe,downThe = getUpTheDownThe(quarterIdThe) #这是我自己写的一个方法，没有错误
busiesses = Business.find_by_sql["SELECT d.name FROM businesses AS b
JOIN employees AS e ON (b.employee_id = e.id)
JOIN departments AS d ON (e.department_id = d.id)
WHERE d.code = Department AND b.out_date <= UpThe AND b.out_date > DownThe ",{:Department => 'department',:UpThe=> 'upThe',:DownThe=> 'downThe'}]
我用的rails，这是在控制里面写的代码，主要是find_by_sql后边的代码有问题，总是提示说参数个数错误，求各位帮忙解决，或者是在model中写这个方法的话代码应该怎样写

[code="sql"]
Business.find_by_sql["SELECT d.name FROM businesses AS b
JOIN employees AS e ON (b.employee_id = e.id)
JOIN departments AS d ON (e.department_id = d.id)
WHERE d.code = ? AND b.out_date <= ? AND b.out_date > ?", department, upThe, downThe]

[/code]

哇靠。LZ，你的代码应该放在code标签里面哎。看的太费劲了,写负复杂的SQL，一不小心就错了。

[code="ruby"]

在model中，定义一些scope（如果是rails3，稍有不同。）
named_scope :xxx, :condition=>[...],:joins=>...
named_scope :yyy, :condition=>[...],:joins=>...

把你的查询条件拆分，或者不能拆分的尽量写成hash，而不是sql字符串。虽然效率会变慢点.....
然后，在controller中，直接当做一个类方法调用。

Business.xxx
Business.xxx.yyy //也可以传参，具体参考API，查一下named_scope就知道具体的用法了，有很详细的例子。

[/code]

{:Department => 'department',:UpThe=> 'upThe',:DownThe=> 'downThe'}
你怎么这样写。。
api

You can use the same string replacement techniques as you can with ActiveRecord#find

Post.find_by_sql ["SELECT title FROM posts WHERE author = ? AND created > ?", author_id, start_date]

[#"The Cheap Man Buys Twice"}>, ...]