原本要两条SQL语句的,我现在只想在一个里执行完,有什么办法吗?
[code="sql"]
select max(fans),min(fans) from tb_fans where userId=#userId#
select * from tb_article where userId bewteen (max) and (min)
其中max代表上面哪条SQL查询的最大值,min代表上面哪条SQL查询的最小值。
注:下面这种方法不行了,多执行了一条SQL语句。
select * from tb_article where userId bewteen (select max(fans) from tb_fans where userId=#userId#) and (select min(fans) from tb_fans where userId=#userId#)
[/code]
MySQL数据库:
[code="java"]
方法一:
select *
from tb_article a,
(select min(fans) as m, max(fans) as n from tb_fans where userId=#userId#) b
where a.userId between b.m and b.n;
方法二:
select *
from tb_article
where userId between
(select min(fans) from tb_fans where userId=#userId#) and
(select max(fans) from tb_fans where userId=#userId#);
[/code]
以上方法MySQL和Oracle测试通过
[code="sql"]
select * from tb_article a
join (select min(userid) mi,max(userid) ma from tb_fans) b
on a.userid between b.mi and b.ma;[/code]