指针数组输出为什么是乱码，请问该怎么改？

题目：
下表是国家和它们的首都：

Australia Canberra
Belgium Brussels
China Beijing
Denmark Copenhagen
England London
France Paris
Greece Athens
Ireland Dublin
Scotland Edinburgh
Wales Cardiff
写一个程序输入一个国家的国家名，输出该国的首都名。

**提示信息："请输入国家名："
**输出格式要求："%s的首都为%s！" "你输入的国家%s没有找到它的首都！"

#include <stdio.h>
#include <stdlib.h>


int main()
{
    char *m[]= {"Australia","Belgium","China","Denmark","England","France","Greece","Ireland","Scotland","Wales"};
    char *n[]= {"Canberra","Brussels","Beijing","Copenhagen","London","Paris","Athens","Dublin","Edinburgh","Cardiff"};
    char x[20];
    int i ;
    printf("请输入国家名");
    scanf("%s",&x[20]);
    for(i = 0; *m[i] == '\n';i++)
    {
        if(*m[i] == x)
        {
           printf("%s的首都为%s！",m[i],n[i]);
        }
        if(*m[i] == '\n')
        {
            printf("你输入的国家%s没有找到它的首都！");
        }
    }



}

之前几种写法都不合适，sizeof(m)算出来是40，是10个指针的大小，而直接写成10，那么指针的意义何在，直接写成数组就行了。
我修改了一下代码，如下，题主可以看看运行一下，自己增减一下国家和首都数量来看看是否合理：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
    char *m[] = { "Australia", "Belgium", "China", "Denmark", "England", "France", "Greece", "Ireland", "Scotland", "Wales" };
    char *n[] = { "Canberra", "Brussels", "Beijing", "Copenhagen", "London", "Paris", "Athens", "Dublin", "Edinburgh", "Cardiff" };
    char x[20];
    int i;
    printf("请输入国家名");
    scanf("%s", &x);
    int count = sizeof(m) / 4;
    for (i = 0; i < count; i++)
    {
        if (strcmp(m[i], x) == 0)
        {
            printf("%s的首都为%s！", m[i], n[i]);
            break;
        }
    }

    if (i == count)
    {
        printf("你输入的国家%s没有找到它的首都！", x);
    }

}

可运行代码：

#include<stdio.h>
#include<stdlib.h>
#include<string.h>


int main()
{
    char *m[]= {"Australia","Belgium","China","Denmark","England","France","Greece","Ireland","Scotland","Wales"};
    char *n[]= {"Canberra","Brussels","Beijing","Copenhagen","London","Paris","Athens","Dublin","Edinburgh","Cardiff"};
    char x[20];
    int i ;
    printf("请输入国家名:\n");
    scanf("%s",x);
    for(i = 0;i < 10;i++)
    {
        if(strcmp(x,m[i]) == 0)
        {
           printf("%s的首都为%s！\n",m[i],n[i]);
           break;
        }
    }
    if(i==10)
         printf("你输入的国家%s没有找到它的首都！\n");


    return 0;
}

结果：

1: x[20]越界了。
2: 不能比较字符串，那样是比较他们的首地址呢。可以用strcmp函数。
3: printf("你输入的国家%s没有找到它的首都！"); 这里没有第二个参数。要在后面加上 ,x 。

char *m[]= {"Australia","Belgium","China","Denmark","England","France","Greece","Ireland","Scotland","Wales"};
char *n[]= {"Canberra","Brussels","Beijing","Copenhagen","London","Paris","Athens","Dublin","Edinburgh","Cardiff"};
char x[20];
int i ;
bool bFind = false;
printf("请输入国家名");
scanf("%s", &x[0]);
for(i = 0; i < sizeof(m) ;i++)
{
if(strcmp(m[i], x) == 0)
{
printf("%s的首都为%s！",m[i],n[i]);
bFind =true;
break;
}
}
if(!bFind)
{
printf("你输入的国家%s没有找到它的首都！");
}