输入m个学生和n门科目,计算并打印每个学生各门科目的总分和平均分 。下列代码哪里错了求大佬T^T

#include
#define stud 30
#define course 5
void total(int *score,int sum[],float aver[],int m,int n);
void print(int *score,int sum[],float aver[],int m,int n);
int main()
{
int i,j,m,n,score[stud][course],sum[stud];
float aver[stud];
printf("学生数:");
scanf("%d",&m);
printf("科数:");
scanf("%d",&n);
printf("input score:\n");
for(i=0;i<m;i++)
{
for(j=0;j<n;j++)
{
scanf("%d",&score[i][j]);
}
}
total(*score,sum,aver,m,n);
print(*score,sum,aver,m,n);
return 0;
}
void total(int*pscore,int sum[],float aver[],int m,int n)
{
int i,j;
for(i=0;i<m;i++)
{
sum[i]=0;
for(j=0;j<n;j++)
{
sum[i]=sum[i]+pscore[i*n+j];
}
aver[i]=(float)sum[i]/n;
}
}
void print(int*pscore,int sum[],float aver[],int m,int n)
{
int i,j;
printf("result:\n");
for(i=0;i<m;i++)
{
for(j=0;j<n;j++)
{
printf("%4d\t",pscore[i*n+j]);
}
printf("%5d\t%6.lf\n",sum[i],aver[i]);
}
}

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#include<stdio.h>

#define stud 30
#define course 5
void total(int *score, int sum[], float aver[], int m, int n);
void print(int *score, int sum[], float aver[], int m, int n);
int main()
{
    int i, j, m, n, score[stud][course], sum[stud];
    float aver[stud];
    printf("学生数:");
    scanf("%d", &m);
    printf("科数:");
    scanf("%d", &n);
    printf("input score:\n");
    for (i = 0; i<m; i++)
    {
        for (j = 0; j<n; j++)
        {
            scanf("%d", &score[i][j]);
        }
    }
    total((int *)score, sum, aver, m, n); //传指针
    print((int *)score, sum, aver, m, n);
    return 0;
}
void total(int*pscore, int sum[], float aver[], int m, int n)
{
    int i, j;
    for (i = 0; i<m; i++)
    {
        sum[i] = 0;
        for (j = 0; j<n; j++)
        {
            sum[i] = sum[i] + pscore[i*course + j]; //这里不是n而是course
        }
        aver[i] = (float)sum[i] / n;
    }
}
void print(int*pscore, int sum[], float aver[], int m, int n)
{
    int i, j;
    printf("result:\n");
    for (i = 0; i<m; i++)
    {
        for (j = 0; j<n; j++)
        {
            printf("%4d\t", pscore[i*course + j]);
        }
        printf("%5d\t%6.f\n", sum[i], aver[i]); // double才是 lf
    }
}