Python地址 地址为什么会这样变化

list = [1,2,3]
print(id(list))
list = [1,2,3]
print(id(list))
list = [1,2,3]
print(id(list))
list = [1,2,3]
print(id(list))

23963968
23963008
23963968
23963008

v应该是恰好重用了链表的地址

你每次写list = [1,2,3]这句话，看似列表内容完全一样，其实还是重新创建了一个新的对象，list这个变量指向了一个新的对象，当然地址就不一样了

id(object)
Return the “identity” of an object. This is an integer which is guaranteed to be unique and constant for this object during its lifetime. Two objects with non-overlapping lifetimes may have the same id() value.

CPython implementation detail: This is the address of the object in memory.

https://docs.python.org/3/library/functions.html?highlight=id#id

 >>> s='s'
>>> print(id(s))
388847220976
>>> s='s'
>>> print(id(s))
388847220976