UITableView从jsonURL加载数据

在UITableview的JSON的URL绑定数据，但是在执行过程中报错。

NSData *response = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];
NSString *json_string = [[NSString alloc] initWithData:response encoding:NSUTF8StringEncoding];
statuses = [parser objectWithString:json_string error:nil];
[self.dropdownTblView reloadData];
for (NSDictionary *status in statuses) 
{
    _altTitle = [status valueForKey:@"Title"];
    NSLog(@"Title %@",_altTitle);
}

- (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView
{
return 1;
}

- (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section
{
   NSLog(@"%d",[statuses count]);
   return [statuses count];

}

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
static NSString *CellIdentifier = @"Cell";

UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier];
if (cell == nil)
{
    cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier] autorelease];
}
return cell;

 //Here I'm getting an error    
id obj = [statuses objectAtIndex:indexPath.row];
NSString *name = [obj valueForKey:@"Title"];
cell.textLabel.text =name;
return cell;
}

JSON内容：

[
  {
    "Id": 1,
    "Title": "Tamil to English",
    "AltTitle": "‡Æ§|‡ÆÆ‡Æø|‡Æ¥‡Øç| |‡ÆÆ‡ØÇ|‡Æ≤|‡ÆÆ‡Øç| |‡ÆÜ|‡Æô‡Øç|‡Æï‡Æø|‡Æ≤|‡ÆÆ‡Øç",
    "Description": "Learn English through Tamil",
    "Code": 1,
    "Version": "1.0",
    "SourceLanguageIndicator": "‡ÆÖ",
    "TargetLanguageIndicator": "A",
    "SourceLanguageCode": "ta",
    "TargetLanguageCode": "en",
    "Updated": "2013-02-21T03:33:19.6601651+00:00"
  }    
]

上面的代码在未执行到你报错的地方的时候,就返回了吧

return cell; //这一句直接就返回了.不会执行下面的代码.

 //Here I'm getting an error    
id obj = [statuses objectAtIndex:indexPath.row];

在同一范围内你返回了两次cell。删除第一次t return cell。并且你在for循环之前调用reloadData 。可能会造成表中的数据源是空的。换成在for循环之后调用reloadData。