为什么界面只能显示下一页的第一条数据

    $(function () {
            $("#btnDelete").click(function () {
                var v;
                var $check = $("#tableUserInfo :checkbox:checked");          
                $check.each(function () {
                    v = $(this).parents("tr").find("td").eq(1).text().trim();

                });
                $.ajax({
                    type: "post",
                    url: "/Handlers/UserInfo.ashx",
                    data: {
                        method: "DeleteUserInfo",
                        UserID:v
                    },
                    dataType: "json",
                    success: function (data) {
                                         $.each(data, function (index, o) {
                                var s = "";
                                s += "<tr>";
                                s += "<td>";
                                s += "<input type='checkbox' name='ck' class='tree-checkbox' />";
                                s += "<td>" + o.UserInfo.UserID + "</td>";
                                s += "<td>" + o.UserInfo.UserName + "</td>";
                                s += "<td>" + o.UserInfo.Cellphone + "</td>";
                                s += "<td>" + o.DepartmentList.DeptName + "</td>";
                                s += "</td>";
                                s += "<td>";
                                s += "<img alt='' title='修改' onclick='UpdateUserInfo(" + o.UserInfo.UserID + ")' src='image/icon_Edit.gif'/>";
                                s += "<img alt='' title='删除' onclick='DeleteUserInfo(" + o.UserInfo.UserID + ")' src='image/icon_Delete.gif' />";
                                s += "</td>";
                                s += "</tr>";
                                $("#tableUserInfo tr:gt(0)").remove();
                                $("#tableUserInfo").append(s);
                                        }
处理程序返回的dt里有5条数据                                     

$("#tableUserInfo tr:gt(0)").remove();
你这里不是添加一条就删除之后继续添加的了。。这句放到each循环外面

 $("#tableUserInfo tr:gt(0)").remove();/////////////////
  $.each(data, function (index, o) {
                                var s = "";
                                s += "<tr>";
                                s += "<td>";
                                s += "<input type='checkbox' name='ck' class='tree-checkbox' />";
                                s += "<td>" + o.UserInfo.UserID + "</td>";
                                s += "<td>" + o.UserInfo.UserName + "</td>";
                                s += "<td>" + o.UserInfo.Cellphone + "</td>";
                                s += "<td>" + o.DepartmentList.DeptName + "</td>";
                                s += "</td>";
                                s += "<td>";
                                s += "<img alt='' title='修改' onclick='UpdateUserInfo(" + o.UserInfo.UserID + ")' src='image/icon_Edit.gif'/>";
                                s += "<img alt='' title='删除' onclick='DeleteUserInfo(" + o.UserInfo.UserID + ")' src='image/icon_Delete.gif' />";
                                s += "</td>";
                                s += "</tr>";
                                $("#tableUserInfo").append(s);
                                        }

我怀疑是不是设置checkbox的默认值了

$.each(data, function (index, o) 你的data只有一个，所以只有一条。虽然你的data里面有五条数据，但是data只有一个。懂我的意思吗