这个xml是生成在手机应用下的data文件夹里的,我想知道读取的时候怎么判断xml是否存在
openFileOutput
Open a private file associated with this Context's application package for writing. Creates the file if it doesn't already exist.
No additional permissions are required for the calling app to read or write the returned file.
所以在默认模式下,不存在就会帮你创建一个。若是要存在的情况下追加,用MODE_APPEND
File creation mode: for use with openFileOutput(String, int), if the file already exists then write data to the end of the existing file instead of erasing it.
http://blog.chinaunix.net/uid-26284395-id-3260936.html
可以使用 File file = new file(path) path就是你的xml的路径,然后通过判断file.exists() 就知道xml存不存在了
同意楼上,File file=new File("Context.getFilesDir()+你的xml名字"); 然后file.exists()判断是否存在