fastJSON解析遇到属性名是数字的怎么办

JSON字符串
{
"error_code": 0,
"reason": "success",
"result": {
"1": "A或者正确",
"10": "BC",
"11": "BD",
"12": "CD",
"13": "ABC",
"14": "ABD",
"15": "ACD",
"16": "BCD",
"17": "ABCD",
"2": "B或者错误",
"3": "C",
"4": "D",
"7": "AB",
"8": "AC",
"9": "AD"
}
}
我不可能建出如下类，也就不能使用fastJSON解析
private String 1;

private String 10;

private String 11;

private String 12;

private String 13;

private String 14;

private String 15;

private String 16;

private String 17;

private String 2;

private String 3;

private String 4;

private String 7;

private String 8;

private String 9;

public void set1(String 1){
this.1 = 1;
}
public String get1(){
return this.1;
}
public void set10(String 10){
this.10 = 10;
}
public String get10(){
return this.10;
}
public void set11(String 11){
this.11 = 11;
}
public String get11(){
return this.11;
}
public void set12(String 12){
this.12 = 12;
}
public String get12(){
return this.12;
}
public void set13(String 13){
this.13 = 13;
}
public String get13(){
return this.13;
}
public void set14(String 14){
this.14 = 14;
}
public String get14(){
return this.14;
}
public void set15(String 15){
this.15 = 15;
}
public String get15(){
return this.15;
}
public void set16(String 16){
this.16 = 16;
}
public String get16(){
return this.16;
}
public void set17(String 17){
this.17 = 17;
}
public String get17(){
return this.17;
}
public void set2(String 2){
this.2 = 2;
}
public String get2(){
return this.2;
}
public void set3(String 3){
this.3 = 3;
}
public String get3(){
return this.3;
}
public void set4(String 4){
this.4 = 4;
}
public String get4(){
return this.4;
}
public void set7(String 7){
this.7 = 7;
}
public String get7(){
return this.7;
}
public void set8(String 8){
this.8 = 8;
}
public String get8(){
return this.8;
}
public void set9(String 9){
this.9 = 9;
}
public String get9(){
return this.9;
}

}
这样肯定报错啊
求大神解答

 String str = "{\"error_code\": 0,"+
            "\"reason\": \"success\","+
            "\"result\": {"+
            "\"1\": \"A或者正确\","+
            "\"10\": \"BC\","+
            "\"11\": \"BD\","+
            "\"12\": \"CD\","+
            "\"13\": \"ABC\","+
            "\"14\": \"ABD\","+
            "\"15\": \"ACD\","+
            "\"16\": \"BCD\","+
            "\"17\": \"ABCD\","+
            "\"2\": \"B或者错误\","+
            "\"3\": \"C\","+
            "\"4\": \"D\","+
            "\"7\": \"AB\","+
            "\"8\": \"AC\","+
            "\"9\": \"AD\"}}";
        JSONObject obj = JSONObject.parseObject(str);
        String result = obj.getString("result");
        JSONObject obj1 = JSONObject.parseObject(result);
        System.out.println(obj1.getString("1"));这不是很正常吗，你那边怎么写的？

解析成object，手动取不行吗，，

第一个类：
package org.atool.json2bean;
import org.codehaus.jackson.annotate.JsonIgnoreProperties;
import org.codehaus.jackson.annotate.JsonProperty;

public class JsonRootBean {

@JsonProperty("error_code")
private int errorCode;
private String reason;
private Result result;
public void setErrorCode(int errorCode) {
     this.errorCode = errorCode;
 }
 public int getErrorCode() {
     return errorCode;
 }

public void setReason(String reason) {
     this.reason = reason;
 }
 public String getReason() {
     return reason;
 }

public void setResult(Result result) {
     this.result = result;
 }
 public Result getResult() {
     return result;
 }

}

第二个类：

package org.atool.json2bean;

public class Result {

private String 1;
private String 2;
private String 3;
private String 4;
private String 7;
private String 8;
private String 9;
private String 10;
private String 11;
private String 12;
private String 13;
private String 14;
private String 15;
private String 16;
private String 17;
public void set1(String 1) {
     this.1 = 1;
 }
 public String get1() {
     return 1;
 }

public void set2(String 2) {
     this.2 = 2;
 }
 public String get2() {
     return 2;
 }

public void set3(String 3) {
     this.3 = 3;
 }
 public String get3() {
     return 3;
 }

public void set4(String 4) {
     this.4 = 4;
 }
 public String get4() {
     return 4;
 }

public void set7(String 7) {
     this.7 = 7;
 }
 public String get7() {
     return 7;
 }

public void set8(String 8) {
     this.8 = 8;
 }
 public String get8() {
     return 8;
 }

public void set9(String 9) {
     this.9 = 9;
 }
 public String get9() {
     return 9;
 }

public void set10(String 10) {
     this.10 = 10;
 }
 public String get10() {
     return 10;
 }

public void set11(String 11) {
     this.11 = 11;
 }
 public String get11() {
     return 11;
 }

public void set12(String 12) {
     this.12 = 12;
 }
 public String get12() {
     return 12;
 }

public void set13(String 13) {
     this.13 = 13;
 }
 public String get13() {
     return 13;
 }

public void set14(String 14) {
     this.14 = 14;
 }
 public String get14() {
     return 14;
 }

public void set15(String 15) {
     this.15 = 15;
 }
 public String get15() {
     return 15;
 }

public void set16(String 16) {
     this.16 = 16;
 }
 public String get16() {
     return 16;
 }

public void set17(String 17) {
     this.17 = 17;
 }
 public String get17() {
     return 17;
 }

}

 JSONObject jsonobj = JSONObject.parseObject(jsonStr);
     JSONObject objs = jsonobj.parseObject("result");
     String x = jo.getString("1");
    这个数字不是你要获得的属性名么，你如果存成一个bean里就自己命名，不需要再写成数字。不要纠结

FastJSON使用心得——如何解析带中文或者数字key的数据
原创 2015年09月20日 19:26:47 标签：json /android 3635
今天群里有人怎么快速解析带中文key或者数字key的json数据，示例数据格式如下：

{
"姓名": "张三",
"年龄": 12
 }

最开始以为没办法使用快速解析了只能一个个的按照键值对来取后来感觉阿里巴巴的大牛应该早就考虑到了这些问题

于是百度了一下发现果然有解决办法直接用注解就好了，实体类写法如下：

[java] view plain copy
public class PeopleBean {

@JSONField(name = "姓名")  
String name;  

@JSONField(name = "年龄")  
int age;  

public String getName() {  
    return name;  
}  

public void setName(String name) {  
    this.name = name;  
}  

public int getAge() {  
    return age;  
}  

public void setAge(int age) {  
    this.age = age;  
}

}

其他的写法就和平时一样了