[{gold,100},{goods,40101,30}]
如果是[{gold,100}]这种格式的,那么我用var exp:RegExp = /{(.*?),(.*?)}/g;这个表达式就可以,但是后面还有3项的,麻烦高手给处理下,谢谢
这个是标准的json,用json解析器而不是正则更简单。
麻烦用正则,谢谢,我这是as3的代码
取出{}的内容后再split下
var s = '[{gold,100},{coin,30000},{wood,30000},{food,30000},{goods,40101,30},{goods,42203,5},{goods,32001,5}]'
var exp = /{([^\}]+)}/g,arr;
while (m = exp.exec(s)) {
arr = m[1].split(',');
console.log(arr)
}
首先谢谢你,但是我不想那样,我想直接根据obj.length判断是2位还是3位的,可以吗?
"obj" [] (@5c1d159)
[0] "{wood,30000}"
[1] "wood"
[2] "30000"
index 25 [0x19]
input "[{gold,100},{coin,30000},{wood,30000},{food,30000},{goods,40101,30},{goods,42203,5},{goods,32001,5}]"
length 3
"obj.length" 3
麻烦正则表达式高手给看看,谢谢
在线等,紧急的,谢谢大家