C 语言基础问题 指针素组 为什么指针p所指向地址会被改变？

#include

char *p[] = {"to","yes","is ok","how do you do ?","holle"};

int main(int argc,char* argv[])
{
int a[5] = {0};
int i = 0;
int j = 0;
char ** t;

t = p;  
    for(i = 0; i<5;i++)
{
    printf("%x \t",p[i]);
}

for(i = 0; i<5; i++)
{
    while( *t[i] != '\0')
    {

        t[i]++;

        a[i]++;
    }
}

for(i =0 ;i<5;i++)
{
    printf("%d \n",a[i]);
}

    for(i = 0; i<5;i++)
{
    printf("%x \t",p[i]);
}

return 0;

}

 #include<stdio.h>
char *p[] = {"to","yes","is ok","how do you do ?","holle"};
int main(int argc,char* argv[])
{
    int a[5] = {0};
    int i = 0;
    int j = 0;
    char * t;//修改
    for(i = 0; i<5;i++)
    {
        printf("%x \t",p[i]);
    }
    printf("\n");
    for(i = 0; i<5; i++)
    {
        t=p[i];//修改
        while( *t != '\0')//修改
        {
            t++;//修改
            a[i]++;
        }
    }

    for(i =0 ;i<5;i++)
    {
        printf("%d \n",a[i]);
    }

    for(i = 0; i<5;i++)
    {
        printf("%x \t",p[i]);
    }
    printf("\n");

    return 0;
}

t=p;

 t[i]++;就相当于p[i]++,所以p[i]最后都指向了字符串末尾。

如何解决？ 让第二个内存地址与第一个一致？